4 years ago

Write the standard form of the equation of the circle with the given center and radius.

1 answer:

4 0

Answer:

make the standard form of the circle taking the negative values of the respective x,y coordinates of the centre and the radius

(x+6)^2+(y+8)^2=r^2

(x+6)^2+(y+8)^2=100

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Reil [10]

19.2m is the answer.

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3 years ago

muminat

Which question???????????

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3 years ago

vredina [299]

The point-slope form:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-2, 7) and (1, 1). Substitute:

$m=\dfrac{1-7}{1-(-2)}=\dfrac{-6}{3}=-2$

$y-7=-2(x-(-2))\\\\\boxed{y-7=-2(x+2)}$ point-slope form

$\boxed{y=-2x+3}$ slope-intercept form

$\boxed{2x+y=3}$ standard form

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3 years ago

sattari [20]

Answer:$80

Step-by-step explanation:

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3 years ago

kenny6666 [7]

The right triangle is also Isosceles. It has two equal angles of 45°.

(hypotenuse)² = 2S²

4 = 2S² => S = √2

Therefore B is the correct answer.

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3 years ago