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3 years ago

Let set C = (1,2,3,4,5,6,7,8) and set D - (2,4,6,8).

1 answer:

6 0

So the problem ask to find the relationship between the set C and set D and the best answer would be letter C. It states the union of the two relationship base on the set of data given in each set

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The teacher recommends that students read for 20 minutes each

OleMash [197]

They wollll complete 3

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3 years ago

What is the solution of x=2+ sqrt x-2

wariber [46]

Answer:

Step-by-step explanation:

$x=2+\sqrt{x-2} \\\\x-2=\sqrt{x-2} \\\\(x-2)^2=\pm(x-2) \\\\x^2-4x+4=\pm(x-2) \\\\$

$x^2-5x+6=0$ OR $x^2+3x+2=0$

x=2 and 3

Hope this helps!

4 0

3 years ago

Read 2 more answers

Can anybody help with this question PLZE!!

Ksivusya [100]

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3 years ago

A piece of aluminum occupies a volume of 12.7 milliliters and weighs 87.3 grams. What is its density of the aluminum rounded to

Katen [24]

Answer:

6.87 g/mL

Step-by-step explanation:

The density of an object can be found by dividing the mass by the volume.

$density=\frac{mass}{volume}\\\\ d=\frac{m}{ v}$

We know that the aluminum occupies a volume of 12.7 milliliters and weighs 87.3 grams. Therefore, the mass is 87.3 g and the volume is 12.7 mL.

$m= 87.3 g\\\\v=12.7 mL$

Substitute the values into the formula.

$d= \frac{87.3 g}{12.7 mL}$

Divide 87.3 g by 12.7 mL

$d=6.87401575 g/mL$

Round to the nearest hundredth. The 4 in the thousandth place tells us to leave the 7 in the hundredth place.

$d= 6.87 g/mL$

The density of the aluminum is about 6.87 grams per milliliter.

3 0

3 years ago

How many protons would make up 9.435 x 10-22 g?

dem82 [27]

Answer:

Mass of proton (m) = 1.67×10^(-27) kg

Step-by-step explanation:

Mass of proton (m) = 1.67×10^(-27) kg.

Since, 1 kg = 1000 g

Therefore, m = 1.67x10^(-27+3) g = 1.67x10^(-24) g

Let N no. of protons be present in 1 g. Hence, Nxm = 1 g

So, N = 1 / m = 1 / (1.67x10^(-24))

N = 6x10^(23) (approx.)

Exact mass of proton gives N = 6.022 x 10^(23).

That is a very special no. In fact, it is the Avogadro’s constant used frequently in chemistry. Avogadro’s no. is actually the number of atoms in exactly 12 g of C-12 isotope of carbon. Since, the atomic mass of C-12 is 12 u (unified mass), then again the no. of carbon atoms turn out to be N.

6 0

3 years ago