Answer:
Yes
Step-by-step explanation:
Permutation :
nPr = n! ÷ (n - r)!
nCr = n! ÷ (n-r)!r!
11 objects taken 3 at a time :
11P3 = 11! ÷ (11 - 3)!
11P3 = 11! / 8!
11P3 = (11 * 10 * 9 )
11P3 = 990
Dividing by 3!
3! = 3*2*1 = 6
= 990 / 6
= 165
For combination :
11C3 = 11! ÷ 8!3!
11C3 = (11 * 10 * 9) / (3 * 2 * 1)
11C3 = 990 / 6
11C3
Answer:
Its Option C.
Step-by-step explanation:
-4x + 7 = 2y - 3
Substitute the given values in the given equation:-
(2,1):- -4(2) + 7 = -1 and 2(1) - 3 = -1 so (2,1) is a solution.
(5, -5):- -4(5) + 7 = -13 and 2(-5) - 3 = -13 so (5, -5) is also a solution.
Answer:
3=180
4=35
Step-by-step explanation:
Answer:
8.75+7.45=16.2. 16.2 is equal to $16.20 so 48.00-16.20=31.8. Jonathan had $31.80 left.
Step-by-step explanation:
Answer:
x = 90 / 3
Step-by-step explanation:
Given : 3 candies cost 90 cents
Given this we want to determine the cost of 1 candy.
To find the cost of "something" given the cost of multiple quantities of that "something" we simply divide the total price by the # of products.
Here the total price is 90 cents and the # of products is 3 ( 3 candies )
This means that the cost of 1 candy ( x ) would be = to 90 / 3
