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denis-greek [22]
3 years ago
7

Name two ways that saving and investing are different

Mathematics
1 answer:
aleksandrvk [35]3 years ago
6 0
Saving and investing are different because investing will generate and duplicate the initial money put it in while savings will stay the same amount without duplicating as it would if it was invested.
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$32,520 divided by 30 people
Ronch [10]

Answer: $1,084 per person

Step-by-step explanation:

divide 32520 by 30

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I need help with 3-4 quick
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3-4 = -1

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23. Which number below could not be used to<br><br><br> PLEASEE HELP!!
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2 years ago
2) A pool is being filled with a hose. The equation y=12x represents the relationship between
faltersainse [42]

Answer:

D)  

Step-by-step explanation:

y = 12x.

A) x=8, so that y = 12(8) = 96.  It's on the line

B) x = 10, so that y = 12(10) = 120.  It's on the line

C) x = 15, so that y = 15(12) = 180.  It's on the line

D) x = 18, so that y = 18(12) = 216, not equal to 206.  So, the point is not on the line.

8 0
2 years ago
32​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
Tems11 [23]

Answer:

a) P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

b) P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

c) P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.32)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

Part b

P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]

P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211  

P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

Part c

P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264

P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218

P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123

P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

6 0
3 years ago
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