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Semenov [28]
3 years ago
14

What are the coordinates of the midpoint?

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
3 0

Answer:

Midpoint (4|7)

Step-by-step explanation:

A(2,6) and B(6,8)

at first add the x values and divide it by two

(2+6)/2=4

second, add the y values and divide it by two

(6+8)/2=7

Midpoint (4|7)

-> and you can see it it is exactly in the middle of line segment

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A graph is shown below. What is the constant and proportionality for the line on the graph below? A:-3/2 B:-2/3 C:2/3 D:3/2
baherus [9]

Answer: -3/2

Explanation: Start from -3 and go over 2 then where u stopped go down 3 from there and over 2 again and u will get -3/2

8 0
3 years ago
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PLS HELP I WILL AWARD BRANLIEST
sveticcg [70]

Answer:

x = 14

2x = 28

6x = 84

Step-by-step explanation:

6x = 180 - 124 + 2x

4x = 56

x = 14

7 0
3 years ago
Solve the system of equations. <br><br> 10x+y=−20 <br><br> y=2x2−4x−16<br><br> ( , ) and ( , )
Sladkaya [172]
I will go about solving this using the elimination method.

First, convert the equations.

10x + y = -20
4x + y = -12

Second, find the easiest variable to get rid of and get rid of it!  (In this case, y)  We will subtract to get rid of y.

6x = -8

Third, you want to solve the equation.

6x = -8 (divide by 6)
x = -1 \frac{1}{3}

Fourth, solve for y by inserting the answer for x into one of the equations.

10(-1 \frac{1}{3}) + y = -20
-13 \frac{1}{3} + y = -20 (subtract -13 \frac{1}{3})
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7 0
3 years ago
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Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

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3 years ago
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Kazeer [188]
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