you should add more detail to your question but you can set up a proportion
There is normally a shape or something to these problems
So to help with the first one
2 / x = 5
multiply the x on both sides
2 = 5x
divide by 5 to isolate the x
2/5 = x
For the second one
We will use the diamond to help us find the common factor
\ 1 /
\ /
\ /
2 / \ 4
/ 3 \
/ \
1) the product
2) and 4) the two numbers
and 3) is sum
10 is the product and -7 is the sum
so what two numbers (factors of 10)
will equal -7 when added
so we have these numbers that will equal the product of +10 and we will need to find the ones that will equal -7 as the sum
10*1, 2*5, -1*-10, -2*-5
if we add the two numbers we will find respectively
11, 7, -11, -7
As you can see that -2 + -5 = +10 and -2+-5= +10
So we have found the two numbers
now before we factor the expression looks like
( x + a) (x + b)
and when factored looks like
x^2 + (a+b)x + (a*b)
Now we can plug in the numbers and solve to see if -2 and -5 are right
(x + -2) (x + -5)
we will factor it
x^2 +-5x + -2x + 10
x^2 + -7x + 10
so a = -2 and b = -5
Hope this helps :)
Given:
The two numbers are
To find:
The highest common factor (HCF) of A and B
Solution:
We have,
...(i)
All the factors of A are prime but the factors of B are not prime. So, it can be written as
...(ii)
From (i) and (ii), it is clear that 3 is the only common factor of A and B. So,
Therefore, the highest common factor (HCF) of A and B is 3.
QP=24 cm
RS=11.25 cm
QS=18.75 cm
<u>Explanation</u>:
Given that TQ bisects <RTP
(1)
consider ΔRQS and ΔRPT
QS||PT,RP and RT are transversals
(alternate angles)(2)
comparing (1) and (2)
and triangle SQT is isocelus
Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)
Therefore <RQS=<RPT(corresponding angles)
<RSQ=<RTP(corresponding angles)
therefore by AA criterion for similarity
ΔRQS~ΔRPT
According to the property of similar triangles
