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ioda
2 years ago
7

Your phone plan gives you 1000 minutes at a cost of $35. if you go over you will be charged $0.12 per minute. This month you use

d 1249 minutes, what is the total charge to your bill
Mathematics
2 answers:
rusak2 [61]2 years ago
6 0

Answer:

Hello! Your answer would be, 400

Step-by-step explanation:

Hope I helped! Ask me anything if you have questions! Brainiest plz. Hope You make a 100%! Have a nice day! -Amelia♥

Tomtit [17]2 years ago
4 0

Answer:64.88

Step-by-step explanation:

1000==35

249 times 0.12=29.88

29.88+25=64.88

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Algebra 2 - Grade 11
saveliy_v [14]

Answer:

for the first equation

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Step-by-step explanation:

my work is attached in a picture.

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2 years ago
There are 112 seats in the school auditorium. There are 7 seats in each row. There are 70 people seated, filming up full rows of
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6 rows are empty.

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4 0
3 years ago
The population in thousands of people of a city is approximated by the function P(t) = 1200(2)0.1038twhere t is the number of ye
asambeis [7]

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Let P represent the population in thousands of people in the year t after 2011

Given the equation:

P=1200(2)^{0.1038t}

a) The population of the group in 2019, that is t = 8(2019 - 2011):

P=1200(2)^{0.1038*8}=2134

b) The population of the group in 2029, that is t = 18(2029 - 2011):

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The population of the group in 2019 is 2,134,000 people

Find out more on equation at: brainly.com/question/2972832

7 0
2 years ago
A) Write the exponential equation to represent a house purchased for
dsp73

Answer:

= A(t) = 120000(1.06)^t   t = 1 year

We just add ^12 to equal 1/12 months.

Then use the notation below.

Step-by-step explanation:

We simply want to write an equivalent form of the same equation that will allow for the time period to be calculated in years.

For one year, t = 1, we want it to grow 6% = 1.06

Yearly Rate of Growth annual equation: = 7200

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To equate monthly we add the exponent  t*12*1/12 before  120000(1.06)^t

then add 1/12 to replace ^t = monthly, or just keep the t= time

A(t) = 120000(1.06)^12t

4 0
2 years ago
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