Answer:
(fg)(x) = 12x^3 + 9x^2 + 28x + 21
Third option
Step-by-step explanation:
(fg)(x) = (3x^2 + 7)(4x + 3)
(fg)(x) = = (3x^2)(4x) + (3x^2)(3) + (7)(4x) + (7)(3)
(fg)(x) = 12x^3 + 9x^2 + 28x + 21
9x + 20y = 109x + 20y
9x = 109x
109x - 9x = 0
100x = 0
x = 0
Answer:
-<u>One Equation</u>: is set equal to a variable
Example:
y = 2x + 1
x + 3y = -12
You already have y, plug it back into x + 3y = -12
x + 3(2x + 1) = -12
x + 6x + 3 = -12
7x + 3 = -12
(Subtract 3 from each side)
7x = -15
(Divide by 7)
x = - 2.14
-<u>No Equation</u>: is set equal to a variable
Example:
2x + y = 10
4× + 2y = -3
Subtract 2x from each side of 2x + y = 10, you should get y= -2x + 10. Now that you have found y, substitute y into 4x+ 2y = -3.
4x + 2(-2x + 10) = -3
4x + -4x + 20 = -3
(Subtract 20 from each side)
4x + -4x = -23
(Add 4x and -4x)
0 = -23
No Solution
<u>-Both</u><u> </u><u>Equations</u>: are set equal to a variable
Example:
y = x + 5
y = -x + 3
(you already have y so plug it into the other equation to solve for x)
-x + 3 = x + 5
(Add -x on both sides)
3 = 2x + 5
(subtract 5 from both sides)
-2 = 2x
(Divide by 2 on each side)
x = -1
I hope this helped!
To reduce down a fraction you can try to find factors that go in both the numerator (top # of fraction) and denominator (bottom #)
So, for 6/9, 3 goes in both of them. When you divide each number by 3 you get:
2/3
