.

Given f(x)=17-x^2, what is the average rate of change in f(x) over the interval [1, 5]?

Art [367]

maybe -6
i could be wrong

6 0

3 years ago

3. A prop for the theater club’s play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round

Mariana [72]

The volume of the prop is calculated to be 2,712.96 cubic inches.

Step-by-step explanation:

Step 1:

The prop consists of a cone and a half-sphere on top. We will have to calculate the volumes of the cone and the half-sphere separately and then add them to obtain the total volume.

Step 2:

The volume of a cone is determined by multiplying $\frac{1}{3}$ with π, the square of the radius (r²) and height (h). Here we substitute π as 3.14. The radius is 9 inches and the height is 14 inches.

The volume of the cone : $V=\pi r^{2} \frac{h}{3}$ = $3.14 \times 9^{2} \times \frac{14}{3}$ = 1,186.92 cubic inches.

Step 3:

The area of a half-sphere is half of a full sphere. The volume of a sphere is given by multiplying $\frac{4}{3}$ with π and the cube of the radius (r³).

Here the radius is 9 inches. We take π as 3.14.

The volume of a full sphere = $V=\frac{4}{3} \pi r^{3}$ = $\frac{4}{3} \times 3.14 \times 9^{3}$ = 3,052.08 cubic inches.

The volume of the half-sphere = $\frac{3,052.08}{2}$ = 1,526.04 cubic inches.

Step 4:

The total volume = The volume of the cone + The volume of the half sphere,

The total volume = 1,186.92 + 1,526.04 = 2,712.96 cubic inches.

5 0

3 years ago

Find the x- and y-intercepts of the following equation: 2x+3y=-24

Ilya [14]

Answer:

Algebra

Topics

How do you find the intercepts of x2y−x2+4y=0?

Algebra Graphs of Linear Equations and Functions Intercepts by Substitution

2 Answers

Gió

Mar 24, 2015

For the intercepts you set alternately x=0 and y=0 in your function:

and graphically:

Answer link

Alan P.

Mar 24, 2015

On the X-axis y=0

So

x2y−x2+4y=0

becomes

x2(0)−x2+4(0)=0

→−x2=0

→x=0

On the Y-axis x=0

and the original equation

x2y−x2+4y=0

becomes

(0)2y−(0)2+4y=0

→y=0

The only intercept for the given equation occurs at (0,0)

Answer link

Related questions

What is the x and y Intercepts?

How many intercepts can a line have?

How do you use substitution to find intercepts?

How do you identify the intercepts on a linear graph?

How do you use the x and y intercepts to graph a linear equation?

How do you find the x and y intercept for y=2x+3?

How do you find the x intercept for y=2?

What is the y intercept for the y=2 graph?

What is the y intercept for x=−1?

How do you find the x-intercept of the line

4 0

2 years ago

Find (F/g)(x) F(x) = sqrt x^2-1 g(x) sqrt x-1

Margaret [11]

Answer:

Option A. √(x + 1)

Step-by-step explanation:

Data obtained from the question include:

f(x) = √(x² – 1)

g(x) = √(x – 1)

(f/g) (x) =..?

(x² – 1) => difference of two square

(x² – 1) => (x – 1)(x + 1)

f(x) = √(x² – 1)

f(x) = √(x – 1)(x + 1)

(f/g) (x) = f(x) /g(x)

f(x) = √(x – 1)(x + 1)

g(x) = √(x – 1)

(f/g) (x) = √(x – 1)(x + 1) / √(x – 1)

(f/g) (x) = √[(x – 1)(x + 1) / (x – 1)]

(f/g) (x) = √(x + 1)

7 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago