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Serjik [45]
3 years ago
5

Given: a and b are parallel and c is a transversal. Prove: ∠2 ≅ ∠7 Parallel lines b and a are cut by transversal c. On line b wh

ere it intersects with line c, 4 angles are created. Labeled clockwise, from uppercase left, the angles are: 1, 5, 6, 2. On line a where it intersects with line c, 4 angles are created. Labeled clockwise, from uppercase left, the angles are: 3, 7, 8, 4. Use the drop-down menus to complete the paragraph proof showing that alternate interior angles are congruent. We know that lines a and b are parallel and that line c is a transversal because that is given. We can tell that angles 2 and 5 are congruent because angles are congruent. Angles 5 and 7 are congruent because angles by parallel lines cut by a transversal are congruent. Therefore, angles 2 and 7 are congruent based on the
Mathematics
2 answers:
shusha [124]3 years ago
6 0

Answer: vertical,corresponding,transitive property

Step-by-step explanation:

trapecia [35]3 years ago
3 0

Answer:

vertical

corresponding

transitive property

Step-by-step explanation:

just took the test

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The U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542. Suppos
xenn [34]

Answer:

(a) P(X > $57,000) = 0.0643

(b) P(X < $46,000) = 0.1423

(c) P(X > $40,000) = 0.0066

(d) P($45,000 < X < $54,000) = 0.6959

Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

<em>Let X = annual salaries in the metropolitan Boston area</em>

SO, X ~ Normal(\mu=$50,542,\sigma^{2} = $4,246^{2})

The z-score probability distribution for normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma }  ~ N(0,1)

where, \mu = average annual salary in the Boston area = $50,542

            \sigma = standard deviation = $4,246

(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

    P(X > $57,000) = P( \frac{X-\mu}{\sigma } > \frac{57,000-50,542}{4,246 } ) = P(Z > 1.52) = 1 - P(Z \leq 1.52)

                                                                     = 1 - 0.93574 = <u>0.0643</u>

<em>The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574</em>.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

    P(X < $46,000) = P( \frac{X-\mu}{\sigma } < \frac{46,000-50,542}{4,246 } ) = P(Z < -1.07) = 1 - P(Z \leq 1.07)

                                                                     = 1 - 0.85769 = <u>0.1423</u>

<em>The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769</em>.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

    P(X > $40,000) = P( \frac{X-\mu}{\sigma } > \frac{40,000-50,542}{4,246 } ) = P(Z > -2.48) = P(Z < 2.48)

                                                                     = 1 - 0.99343 = <u>0.0066</u>

<em>The above probability is calculated by looking at the value of x = 2.48 in the z table which gave an area of 0.99343</em>.

(d) Probability that the worker’s annual salary is between $45,000 and $54,000 is given by = P($45,000 < X < $54,000)

    P($45,000 < X < $54,000) = P(X < $54,000) - P(X \leq $45,000)

    P(X < $54,000) = P( \frac{X-\mu}{\sigma } < \frac{54,000-50,542}{4,246 } ) = P(Z < 0.81) = 0.79103

    P(X \leq $45,000) = P( \frac{X-\mu}{\sigma } \leq \frac{45,000-50,542}{4,246 } ) = P(Z \leq -1.31) = 1 - P(Z < 1.31)

                                                                      = 1 - 0.90490 = 0.0951

<em>The above probability is calculated by looking at the value of x = 0.81 and x = 1.31 in the z table which gave an area of 0.79103 and 0.9049 respectively</em>.

Therefore, P($45,000 < X < $54,000) = 0.79103 - 0.0951 = <u>0.6959</u>

3 0
3 years ago
Can someone plz help me with this math problem?
ohaa [14]
Cheese $1.99 * 1/2 = $1.00
Sliced Ham $3.29 * 3 = $9.87
Bread $1.59 * 2 = $3.18
Potato Chips $3 * 2 = $6
Salsa $1.39 * 1 = $1.39
Total $1.00+$9.87+$3.18+$6+$1.39
Total Spent $21.44

Coupon 1 $21.44-$4.00=$17.44
Coupon 2 $21.44 * 10% = $2.14
$21.44 - $2.14 =$19.30

Coupon 1 will save you the most money
6 0
4 years ago
Read 2 more answers
There are seven members of a jazz club who are listed below. A concert director can choose some or all of them to be part of a l
balu736 [363]
The concert director can choose the new members by holding try outs to take the the possible candidate’s skills, performance and professionalism into consideration to be a part of the large show. Another way is by voting amongst other people in their school to see who the audience would be excited to see preforming in the show.
4 0
3 years ago
What is the percentage of 18/20
labwork [276]
18/20 is 90%

You can use a calculator to divide 18 and 20 and you will get 0.9 which is 90%

Or. simplify by dividing the top and bottom by 2, to get 9/10 which is still 90%

:)
7 0
3 years ago
Read 2 more answers
Multiply (2+a+b) 6)
PSYCHO15rus [73]
2+2+2=(6
(a2)
(b2)
2×2=4+2=6
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3 years ago
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