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Fantom [35]
3 years ago
14

Find the x and y intercepts of the quadratic equation f(x)=-x^2+4x-4

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0
<u>X - Intercept</u>
f(x) = -x² + 4x - 4
   0 = -x² + 4x - 4
   x = <u>-(4) +/- √((4)² - 4(-1)(-4))</u>
                         2(-1)
   x = <u>-4 +/- √(16 - 16)</u>
                    -2
   x = <u>-4 +/- √(0)
</u>               -2<u>
</u>   x = <u>-4 +/- 0
</u>              -2<u>
</u>   x = <u>-4 + 0</u>      x = <u>-4 - 0</u>  
            -2                 -2
   x = <u>-4</u>             x = <u>-4</u>
         -2                   -2
   x = 2               x = 2

The solution to the problem is {2, 2}, or {2}. The x - intercept of the problem is (2, 0).

<u>Y - Intercept</u>
f(x) = -x² + 4x - 4
f(x) = -(0)² + 4(0) - 4
f(x) = -(0) + 0 - 4
f(x) = -0 + 0 - 4
f(x) = 0 - 4
f(x) = -4

The y - intercept of the problem is (0, -4).
<u />
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