Find the x and y intercepts of the quadratic equation f(x)=-x^2+4x-4

1 answer:

8 0

X - Intercept
f(x) = -x² + 4x - 4
 0 = -x² + 4x - 4
 x = -(4) +/- √((4)² - 4(-1)(-4))
 2(-1)
 x = -4 +/- √(16 - 16)
 -2
 x = -4 +/- √(0)
 -2
 x = -4 +/- 0
 -2
 x = -4 + 0 x = -4 - 0
 -2 -2
 x = -4 x = -4
 -2 -2
 x = 2 x = 2

The solution to the problem is {2, 2}, or {2}. The x - intercept of the problem is (2, 0).

Y - Intercept
f(x) = -x² + 4x - 4
f(x) = -(0)² + 4(0) - 4
f(x) = -(0) + 0 - 4
f(x) = -0 + 0 - 4
f(x) = 0 - 4
f(x) = -4

The y - intercept of the problem is (0, -4).

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