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3 years ago

Find the slope of the line that goes through the given points. (-9, -7) and (-7,9)

Mathematics

2 answers:

nika2105 [10]3 years ago

7 0

Answer: 8

Step-by-step explanation:

slope = rise/run

slope = (-7-9)/(-9-(-7)) = -16/-2 = 8

ycow [4]3 years ago

7 0

Equation:

Y2-Y1
———
X2-X1

9 - -7 = 16
-7 - -9= 2

16/2= 8
The slope of the line is 8.

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What is y squared times 9 to the 5th power

Black_prince [1.1K]

So y^2 times 9^5 or
y*y means y times y so

y*y*9*9*9*9*9 or 59049y^2

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3 years ago

The expression to find the perimeter of a rectangle is 2(length + width). What is the 1 perimeter, in units, of a rectangle of l

Svetradugi [14.3K]

The answer would be 18 units I believe

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8 0

2 years ago

Read 2 more answers

Prove that if two lines intersect each other then the vertically opposite angles are equal.

Svetradugi [14.3K]

If two lines intersect each other then the vertically opposite angles are equal.

A line is a one-dimensional figure, which has length but no width. A line is made of a set of points which is extended in opposite directions infinitely.

To prove, two lines intersect each other then the vertically opposite angles are equal.

Suppose there are two lines AB and CD intersecting at a point O.

So, the angles a and c ; b and d are vertically opposite.

Now taking line AB,

Since sum of angles made on a straight line is 180°.

Thus ∠a + ∠b = 180° ...(i)

Similarly taking line CD,

∠b + ∠c = 180° ....(ii)

Comparing eq (i) and (ii) we get,

∠a + ∠b = ∠b + ∠c

Therefore, we get

∠a = ∠c

which are vertically opposite angles.

Taking line CD,

Since sum of angles made on a straight line is 180°.

Thus ∠c + ∠b = 180° ...(iii)

Similarly taking line CD,

∠c + ∠d = 180° ....(iv)

Comparing eq (iii) and (iv) we get,

∠c + ∠b = ∠c + ∠d

Therefore, we get

∠b = ∠d

which are vertically opposite angles.

Thus, if two lines intersect each other then the vertically opposite angles are equal.

To learn more about angles:

brainly.com/question/11337367

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7 0

2 years ago

The area of rectangle ABCD is 72 square inches. A diagonal of rectangle ABCD is 12 inches and the diagonal of rectangle EFGH is

luda_lava [24]

Answer:

The area of rectangle EFGH is $242\ in^{2}$

Step-by-step explanation:

For this problem I assume that rectangle ABCD and rectangle EFGH are similar

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor

Let

z ------> the scale factor

The scale factor is the ratio between the diagonals of rectangles

$z=\frac{22}{12}=\frac{11}{6}$

step 2

Find the area of rectangle EFGH

we know that

If two figures are similar, then the ratio of its areas is the scale factor squared

Let

z------> the scale factor

x -----> area of rectangle EFGH

y ----> area of rectangle ABCD

$z^{2}=\frac{x}{y}$

we have

$z=\frac{11}{6}$

$y=72\ in^{2}$

substitute and solve for x

$(\frac{11}{6})^{2}=\frac{x}{72}$

$\frac{121}{36}=\frac{x}{72}$

$x=\frac{121}{36}(72)$

$x=242\ in^{2}$

4 0

2 years ago

Find the difference of the following polynomials:<br> (-2r4 + 3r3 - 10) and (4r4 - p3 + 2r2 + 7).

Vilka [71]

$-6 r^{4}+4 r^{3}-2 r^{2}-17$ is the difference between $-2 r^{4}+3 r^{3}-20 \text { and } 4 r^{4}-p^{3}+2 r^{2}+7$

Step-by-step explanation:

Given equations,

$-2 r^{4}+3 r^{3}-20 \text { and } 4 r^{4}-p^{3}+2 r^{2}+7$

Difference of the polynomial is written as

$=-2 r^{4}+3 r^{3}-20-\left(4 r^{4}-p^{3}+2 r^{2}+7\right)$

Open the brackets and multiply with -1 the whole expression $\left(4 r^{4}-p^{3}+2 r^{2}+7\right)$ becomes

$=-2 r^{4}+3 r^{3}-20-4 r^{4}+p^{3}-2 r^{2}-7$

$=-6 r^{4}+4 r^{3}-2 r^{2}-17$

This is the difference of given two polynomials is $-6 r^{4}+4 r^{3}-2 r^{2}-17$ .

4 0

2 years ago