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Pavel [41]
3 years ago
14

(-3,3) 8 units down and 7 units right

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:

look it up

Step-by-step explanation:

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How do I slove this eqaution, and whats the answer?<br> -3(n+6)+10=-9
Sauron [17]

Answer:

n = \frac{1}{3}

Step-by-step explanation:

  1. Apply the distributed property, so it now looks like this: -3n + -18 + 10 = -9
  2. Combine like terms: -3n + -8 = -9
  3. Simplify: -3n - 8 = -9
  4. Add 8 to each side, so it now looks like this: -3n = -1
  5. Divide each side by -3 to cancel out the -3 next to n. It should now look like this: n = 1/3

I hope this helps!

8 0
3 years ago
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
Work out the area of this triangle.<br><br> I will mark you as brainliest, please help quick.
nataly862011 [7]

Answer:

<u><em>22 cm²</em></u>

Step-by-step explanation:

Work out the area of this triangle.

Area Formula: 1/2b * h where b = base (11cm) and h = height (4 cm)

1/2 *11 * 4 =

5.5 * 4 =

<u><em>22 cm²</em></u>

3 0
2 years ago
90 plus what equals 395
rodikova [14]
305 plus 90= 395. Found by doing 395-90
5 0
3 years ago
Read 2 more answers
Write a variable expression to describe the rule for the sequence. Then find the 100th term. 35, 36, 37,...
Dmitry [639]

Given expression is 35, 36, 37, 38...

First term a = 35

Common difference d = 36-35 = 1

Nth term of arithmetic sequence is:

n_{th} = a+ (n-1)d

n_{th}= 35+(n-1)(1)

n_{th} = 34+n

To find the 100th term, substitute n = 100

n_{100} = 34 +100

n_{100} =134

Correct option is B

5 0
3 years ago
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