3 years ago

(-3,3) 8 units down and 7 units right

Mathematics

1 answer:

Alexus [3.1K]3 years ago

8 0

Answer:

look it up

Step-by-step explanation:

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In triangle ABC, AB = 11 cm, BC = 9 cm and CA = 10 cm. Find the area of triangle ABC.

max2010maxim [7]

Answer:

Area = 42.43 square cm

Step-by-step explanation:

Using Heron's Formula :

$Area = \sqrt{s\times (s-a) \times (s-b) \times(s -c)} \ , \ where \ s \ =\ \frac{a+ b+ c}{2}$

Find Area :

$s = \frac{11 + 9 + 10 }{2} = \frac{30}{2} = 15$

$Area = \sqrt{15 \times ( 15 - 11 ) \times { (15 - 9 ) \times ( 15 -10)}\\\\$

$= \sqrt{15 \times 4 \times 6 \times 5}\\\\=\sqrt{1800}$

$= 42 . 43 \ cm^2$

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