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melomori [17]
3 years ago
15

What is the correct answer? please only put the answer.

Mathematics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

156

Step-by-step explanation:

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Solve -24 + (1-4)^2​
ElenaW [278]

Answer:

-15

Step-by-step explanation:

-24 + (1-4)^2​    (solve parentheses first)

= -24 + (-3)^2 (solve exponent)

= -24 + 9

= -15

6 0
3 years ago
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The roots of a quadratic equation ax2+bx+c=0 are 1+i 5 and 1−i 5 . Find possible values of a, b and c.
Anarel [89]

Answer:

Step-by-step explanation:

If the roots are 1 + 5i and 1 - 5i, then you need the factors that result from those roots.  They are (x - 1 + 5i) and (x - 1 - 5i).  Now what you do with those is FOIL them out.  Doing that gives you the following:

x^2-x+5ix-x+1-5i-5ix+5i-25i^2 (what a mess, huh?)

The good thing is that several of those terms cancel each other out.  +5ix cancels out the -5ix; -5i cancels out the 5i; and the 2 -x terms combine to -2x.  That leaves you with:

x^2-2x-25i^2

Obviously you're in the section in math that deals with complex (imaginary) numbers so you should know that i-squared is equal to -1.  Making that replacement:

x^2-2x+25

a = 1, b = -2, c = 25

6 0
3 years ago
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Evaluate the expression a + c for a = 22 and c = 11.
bixtya [17]

Answer: 33

Step-by-step explanation: substitute a with 22 and c with 11.

22+11=33

4 0
3 years ago
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What is the x-coordinate of the point that divides the directed line segment from K to J into a ratio of 1:3?
ruslelena [56]
Since we need a point that divides K-->J into two segments in a 1:3 ratio, let's flip it to a 3:1 ratio in the J-->K direction. That means that this point is 3/(3+1) = 3/4 of the way up line JK.
Let's take 3/4 of the x of K (plus the 1 for the x of J):
3/4×(9 - 1) + 1 (because the beginning ofvthe line, at J, has an x of 1)...
3/4×(8) + 1 = 6 + 1 = 7
Therefore the answer is C) 7
4 0
4 years ago
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In order to find constant rate, you need to use change in y ÷ change in x right?
NemiM [27]

Yes u have to and as long are you do than you would be right

3 0
3 years ago
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