Let's assume that the faster car has a 2 mile "head start".
The faster car is 1.2 times faster (48/40) than the slower car.
It will take five 2 mile trips to "catch" the other car.
Five 2 mile trips will take 5 * 40 seconds = 200 seconds.

6 0

3 years ago

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A $79 television is on sale for $65. What percent discount was given? <br>

pickupchik [31]

Answer:

The discount percentage has been given: ($ 65 / $ 79) x 100 = 82.27%

So the discount percentage is: 100% -82.27% = 17.72%

Step-by-step explanation:

6 0

3 years ago

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The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt

Marizza181 [45]

Answer:

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

$L=w+2$

now, we can find area

$A=L\times W$

now, we can plug it

$A=(w+2)\times w$

$A=w^2+2w$

we are given area =6

so, we can set it equal

and then we can solve for w

$w^2+2w=6$

$w^2+2w-6=0$

we can use quadratic formula

$ax^2+bx+c=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

$w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}$

$w=-1+\sqrt{7},\:w=-1-\sqrt{7}$

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

7 0

3 years ago