Which represents a function? Edge 2020.

Mathematics

1 answer:

neonofarm [45]3 years ago

7 0

The data set {(-8,-2),(-4,1),(0,-2),(2,3),(4,-4)} represents a function because for every distinct input x has only one output y, whereas all the other data sets have at least one point of x in which has two or more outputs of y.

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a crate of strawberries costs $4 each or three crates cost $10. what is the minimum cost for $20 crates.

timofeeve [1]

The minimum cost for 20 crates would be 68 dollars. You would buy 18 crates using the 3 for 10 dollars ( this would cost 60 dollars), and then 2 crates using the one crate for 4 dollars (this would cost 8 dollars) all together you would have 20 crates, costing you 68 dollars.

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3 years ago

On a coordinate plane, a triangle is reflected across y = negative 2.

AleksandrR [38]

Answer:

The answer will be D.y=-2

Step-by-step explanation:

The reflection line is the fixed line that a shape or figure is reflected across of. The problem tells you that the triangle is reflected across y=-2

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3 years ago

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A postcard in the shape of a parallelogram has an area of 12in^2. What are two possible lengths of bases and heights for the pos

Tpy6a [65]

A postcard is in the shape of a parallelogram. A parallelogram is a quadrilateral with two pair of parallel sides, opposite sides and opposite angles are equal.

Since, the postcard has an area of 12 square inches.

Since, area of parallelogram = $base \times height$

As area of parallelogram is 12, it means that the product of base and height is 12 square inches.

So, the possible dimensions of postcard are 3 inches and 4 inches and 2 inches and 6 inches.

So, base = 3 inches , height = 4 inches or base = 4 inches , height = 3 inches.

So, base = 2 inches, height = 6 inches or base = 6 inches , height = 2 inches.

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3 years ago

Which expression is equivalent to ?

mamaluj [8]

Answer:

Step-by-step explanation:

$\frac{(a^{2}b^{4}c)^{2}*(6a^{3}b)*(2c^{5})^{3}}{4a^{6}b^{12}c{^3}}\\\\=\frac{a^{2*2}b^{4*2}c^{2}6a^{3}b2^{3}c^{5*3}}{4a^{6}b^{12}c{^3}}\\\\=\frac{a^{4}b^{8}c^{2}6a^{3}b8c^{15}}{4a^{6}b^{12}c{^3}}\\\\=\frac{6*8*a^{4+3}b^{8+1}c^{2+15}}{4a^{6}b^{12}c{^3}}\\\\=\frac{6*2*a^{7}b^{9}c^{17}}{a^{6}b^{12}c{^3}}\\\\=\frac{12a^{7-6}c{17-3}}{b^{12-9}}\\\\=\frac{12a^{1}c^{14}}{b^{3}}\\\\=\frac{12ac^{14}}{b^{3}}$