Here's one way to do it.
AB ≅ AC . . . . . . . . . . given
∠BAY ≅ ∠CAY . . . . given
AY ≅ AY . . . . . . . . . . reflexive property
ΔBAY ≅ ΔCAY . . . .. SAS congruence
XY ≅ XY . . . . . . . . . . reflexive property
∠AYB ≅ ∠AYC . . . . CPCTC
BY ≅ CY . . . . . . . . . . CPCTC
ΔXYB ≅ ΔXYC . . . .. SAS congruence
Therefore ...
∠XCY ≅ ∠XBY . . . . CPCTC
sorry ill give points back
it's this tally/nathan?
Bsbdbsvdbhdbd. Dhhdhdhdhdh. Dhhdhdhdhdhdg. Dhhdhdhdh
Answer:
Step-by-step explanation:
ooooh I loved these. ok. so if you have a set of lines like this, we will just use an "x" as an example for lines crossing. if you have 100 as the angle on the top, then the angle on the bottom will be exactly the same. the top and bottom are the same angle ALWAYS. the angles across from each other are the same. because brainly will timeout on me if I stop typing, I will post this and later I will post a picture of the first few finished as an example so you get what i'm talking.