Answer:
This is the “best” method whenever the quadratic equation only contains x2 terms.
The general approach is to collect all x2 terms on one side of the equation while keeping the constants to the opposite side.
step by step: but in order to solve a quadratic using the square root principle the problem must be in the correct form. To solve a quadratic using the square root principle the quadratic must be in vertex form, a(x – h)2 + k.
Answer:
-5/3
Step-by-step explanation:
Perpendicular lines have negative reciprocal slopes.
Answer:
The solution for the system of linear equations 3x-y=10 and 2x+y=5 is x=3 y= -1
<u>Solution:
</u>
Given that two linear equations are 3x-y = 10 and 2x + y = 5
We have to find the values of “x” and “y”
Let us consider 3x – y =10 ---- eqn 1
2x + y = 5 --- eqn 2
From eqn 1 , rearranging the terms we get
y = 3x-10 --- eqn 3
By substituting the value of “y” from eqn 3 into eqn 2 we get,
2x + 3x – 10 = 5
On solving above expression, 5x – 10 = 5
5x = 15
x = 3
Substitute the value of “x” in eqn 1 to obtain “y” value
3(3) – y = 10
9 – y = 10
y = 9-10 = -1
Hence the solution for the system of linear equations 3x-y=10
and 2x+y=5 is x=3 and y= -1
Angle x and <117 are supplementary meaning they equal 180 degrees so x has to equal 63. which is the first option on the right
The arithmetic sequences are 3rd one, and 5th one as they are increasing or decreasing by a constant rate of change
