Ipsec is considered to be a transparent security protocol because IPsec (Internet Protocol Security) is designed so that modifications of programs, additional training, additional client setup are not allowed. It <span>provide security </span>functions<span>, authentication and encryption, at the IP (Internet Protocol) level. </span>
The answer is the Quick Access Toolbar. However, it is not only for saving files or undoing your work. Containing a set of commands that are independent, this toolbar is actually customizable wherein you could change these icons to the ones you really need and frequently use. By tweaking the settings, you can even add commands to the Quick Access Toolbar that are not in the ribbon (like New, Open and Print).
Answer:
1. 45
2. 9
3. 11
4. 17
Explanation:
Given the following:
28 checked H
26 checked C
14 checked D
8 checked H and C
4 checked H and D
3 checked C and D
2 checked all.
Hence N(H) = 28
N(C) = 26
N(D) = 14
N(H U C) = 8
N(H U D) = 4
N(C U D) = 3
N(H U C U D) = 2
We also know that
Total = N(H) + N(C) + N(D) - N(H U C) - N(H U D) - N(C U D) + N(H U C U D)
Substituting the given values, we obtain
Total = 55
1. Students that didn't check any box = 100 - 55 = 45 students
2. Students who checked exactly two box
= N(H U C) + N(H U D) + N(C U D) - 3N(H U C U D) (from probability theorem)
Substituting the values, we have 8 + 4 + 3 - 6 = 9 students
3. Students who checked atleast two box =
The people who have checked all three are needed to be calculated once. Earlier, we subtracted them thrice so we add one time
N(H U C) + N(H U D) + N(C U D) - 2N(H U C U D) = 8 + 4 + 3 - 4 = 11 students
4. Given N(C) = 26
We subtract N(CUD) and N(HUC) as they have checked another apart from club.
26 -8 - 3 = 15
Now we could notice we have subtracted N(HUCUD) twice in both categories, so we add one time to neutralise
15 + 2 = 17
Hence N(only C) = 17 students.
I believe the answer is true :)
