Find an equation for the contour of f(x,y)=2x2y+7x+20f(x,y)=2x2y+7x+20 that goes through the point (3,−2)(3,−2).

1 answer:

6 0

That equation will be
.. f(x, y) = f(3, -2)
.. 2x^2y +7x +20 = 2*3^2*(-2) +7*3 +20

2x^2*y +7x +20 = 5

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