A baseball teams starting lineup has 3 left handed hitter, 4 right handed hitter, and 2 switch hitters . if there are a total of
81 baseball players in the league , how many player could be expected to NOt be a right handed hitter ?
1 answer:
Answer: 45 players
Step-by-step explanation:
4+3+2=9 9x9=81 9x2=18. 9x3=27 27+18=45
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110grams÷22 =5
5+8+ 9 =22
5 x5=25
5x8=40
5x9=45
The ratio is 25:40:45
10% of 50 is 5.
Therefore 50+5=55
Your answer is 5
Answer:
This is multiplicative identity in which 4✖️1=4
Step-by-step explanation:
Hope it will help you:)
Dividing by a fraction is like multiplying with the inverse.
So 14 / (2/7) is the same as 14 * 7/2, which is 49
Using a calculator, you can find out that
and so that means
so your answer is
