Answer:
d^2 - π(d/2)^2
Step-by-step explanation:
Since the diameter of the circle is equal to the side of a square (d), that means that we have a circle inscribed in square.
If we draw a square and inscribe a circle in it, all parts of the square outside the circle will be waste, in this particular case.
If we want to find the area of the wasted material we need to subtract the area of the circle from the area of the square.
Area of the circle is:
P1 = πr^2, r being the radius
Since radius is half the diameter, that means that:
P1 = π • (d/2)^2
Area of the square whose side is d is:
P2 = d^2
So, the area of wasted material is:
P = P2 - P1
P = d^2 - π(d/2)^2
Step 2 was his error.
The following problem is solved by Alan:
In solving for x, you have to cross multiply between the numbers.
In that case, step 2 would look like this:
(25)(x) = (8)(200)
NOT THIS:
(8)(x) = (25)(200)
Now continue all the way.
25x = 1600
x = 1600 ÷ 25
x = 64
Answer:
m∠WXY+m∠ZXY=m∠WXZ
Step-by-step explanation:
You don't know the angles to be congruent (equal measures), complementary (measures add to 90 deg), or supplementary (measures add to 180 deg); all you know is that they are adjacent, so the sum of the measures of the two smaller angles equals the measure of the larger outer angle.
Answer: m∠WXY+m∠ZXY=m∠WXZ
do you need to include the wiggle infront of the first bracket? if not;
(x+1) ÷ [(x^2+2) x (2x-3dx)]
x^2 x 2x = 2x^3
x^2 x -3dx = -3dx^3
2 x 2x = 4x
2 x -3dx = - 6dx
i cant find a way to make it equal 0 so i think the answer is just
x+1 over 2x^3 - 3dx^3 + 4x - 6dx as a fraction
