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Delicious77 [7]
3 years ago
10

THREE QUESTIONSS PLEASE HELP !!!

Mathematics
2 answers:
Olenka [21]3 years ago
4 0

Answer:

1. B

2. C

3. C

Step-by-step explanation:

Sliva [168]3 years ago
3 0

Answer:

1. D: 6      2.A:y=0.1x + 2      3.C

Step-by-step explanation:

1. In y = mx + b, b represents the y-intercept. The equation is alreayd in y = mx +b, so we can see that 6 is b, making it the y-inetrcept.

2. A is the only one written in slope intercept form, or y = mx + b.

3. -8x + 4y = 10 written in slope intercept form is y  = 2x + 5/2. The slope is shown by 2.

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Please Answer I don't understanddd
Tamiku [17]
C = 2 pi r given r = 4
so
C = 2 pi (4)
C = 8 pi

answer
C. C = 8pi 
3 0
3 years ago
ANSWER AND EXPLAIN PLEASE ILL MARK BRAINLIEST!!!!!!!!!!!
motikmotik

Answer:

x = 1 and y = -2

Step-by-step explanation:

Given that,

2x-3y = 8 ..(1)

4x+3y = -2 ..(2)

Add equation (1) and (2),

2x-3y+4x+3y = 8+(-2)

6x = 6

x = 1

Put the value of x in equation (1).

2-3y = 8

2-8 = 3y

-6 = 3y

y = -2

Hence, the value of x is 1 and that of y is -2.

3 0
3 years ago
What is the lcm of 56 and 136
Citrus2011 [14]

Answer:

LCM(56,136)=952

Step-by-step explanation:

To find the LCM of two numbers, factorize both these numbers:

56=2\cdot 28=2\cdot 2\cdot 14=2\cdot 2\cdot 2\cdot 7=2^3\cdot 7\\ \\136=2\cdot 68=2\cdot 2\cdot 34=2\cdot 2\cdot 2\cdot 17=2^3\cdot 17

These two numbers have the common factor of 2^3.

Now multiply this common factor by the remaining factors:

LCM(56,136)=2^3 \cdot 7\cdot 17=952

Therefore, the LCM is 952.

8 0
3 years ago
A rectangle’s perimeter and it area have the same numerical value. The width of the rectangle is 3 units. What is the length is
Verdich [7]

Answer:

6

Step-by-step explanation:

3+3+6+6=18

3*6=18

5 0
3 years ago
Using sum or difference formulas, find the exact value of sin(165∘)
Nikitich [7]
\bf \textit{Sum and Difference Identities}
\\ \quad \\
sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\ \quad \\
sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})\\\\
-------------------------------\\\\

\bf sin(165^o)\implies sin(120^o+45^o)
\\\\\\
sin(120^o)cos(45^o)~+~cos(120^o)sin(45^o)\implies \cfrac{\sqrt{3}}{2}\cdot \cfrac{\sqrt{2}}{2}~+~\cfrac{-1}{2}\cdot \cfrac{\sqrt{2}}{2}
\\\\\\
\cfrac{\sqrt{6}}{4}~-~\cfrac{\sqrt{2}}{4}\implies \cfrac{\sqrt{6}-\sqrt{2}}{4}
6 0
3 years ago
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