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nalin [4]
3 years ago
7

Given f(x) = –7x + 9 and h(x) = –5(–7x + 9), what are the slope and y-intercept of the graph of function h?

Mathematics
2 answers:
Ierofanga [76]3 years ago
8 0

Answer:

h(x): Slope(m) = 35, Y-intercept(c) = -45

f(x): Slope(m) = -7, Y-intercept(c) = 9

Step-by-step explanation:

We are given the functions in the question:

f(x) = -7x + 9\\h(x) = -5(-7x + 9)

We have to find the slope and y-intercept of the graph of function h(x).

First we simplify h(x)

h(x) = -5(-7x + 9)\\h(x) = -5(-7x) + (-5)(9)\\h(x) = 35x -45

Comparing the equation to the point slope form of the straight line, we have,

y = mx + c

where m is he slope of line and c is the y-intercept that is the value of y when x is zero.

Comparing, we get,

Slope, m = 35

Y-intercept, c = -45

For function f(x), we have

Slope, m = -7

Intercept, c = 9

taurus [48]3 years ago
4 0

The Slope of f(x) = –7x + 9  is (-7)

The slope of  h(x) = –5(–7x + 9) is (35)

The y-int of h(x) is (-45).

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A rectangular dining room table top is 36 inches wide the diagonal to tabletop measures 85 inches how many inches long is a tabl
makvit [3.9K]
Pythagorean theorem: a^2 + b^2 = c^2
36^2 + b^2 = 85^2
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6 0
3 years ago
Of the coffee makers sold in an appliance​ store, 4.0% have either a faulty switch or a defective​ cord, 2.5% have a faulty​ swi
lukranit [14]

Answer: Hence, Probability that a coffee maker will have a defective cord is 0.376=37.6%.

Step-by-step explanation:

Since we have given that

Let A be the event of getting a faulty switch.

Let B be the event of getting a defective cord.

Here, P(A∪B) = 4% = 0.04

P(A∩B) = 0.1% = 0.001

P(A) = 2.5% = 0.025

We need to find P(B):

As we know that

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\0.04=P(A)+0.025-0.001\\\\0.04=P(A)+0.024\\\\P(A)=0.04-0.024=0.376

Hence, Probability that a coffee maker will have a defective cord is 0.376=37.6%.

6 0
3 years ago
A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the
leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em />I \to<em> I-Beam</em>

<em />d_I \to<em> distance between I beam and the bridge</em>

<em />b \to<em> distance between each I beam</em>

<em />

Given that:

I = \frac 34 ft\\

d_I = 3 ft

<em />Length = 55ft\ 6in<em> --- length of the  bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

L_1 = 6 \times I

L_1 = 6 \times \frac 34

L_1 = \frac {18}4

L_1 = 4.5ft

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

d_1 =2 \times d_I

d_1 =2 \times 3ft

d_1 =6ft

There are 5 spaces between the I-beams

So, the length of the total spaces is:

L_2 = 5 \times b

L_2 = 5b

The total length is:

Length = L_1 + d_1 + L_2

So, we have:

4.5ft + 6ft + 5b = 55ft\ 6in

Collect like terms

5b = 55ft\ 6in - 4.5ft - 6ft

5b = 44.5ft\ 6in

Convert inches to feet

5b = 44.5ft\ + \frac{6}{12}ft

5b = 44.5ft\ + 0.5ft

5b = 45ft

Divide both sides by 5

b = 9ft

<em>Hence, the distance (b) between each beam is 9ft.</em>

Read more about lengths at:

brainly.com/question/22059747

3 0
2 years ago
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