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3 years ago

Solve x2 + 9x + 9 = 0. (2 points)

Mathematics

1 answer:

____ [38]3 years ago

3 0

Answer:

Letter A.

Step-by-step explanation:

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Solve: 3x-8 = 6(1 – 2x) +16

leva [86]

Answer:

x=2

Step-by-step explanation:

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2 years ago

What are skew lines and parallel lines

Leni [432]

Two or more lines are parallel when they lie in the same plane and never intersect. The symbol for parallel is ||. To mark lines parallel, draw arrows (>) on each parallel line. If there are more than one pair of parallel lines, use two arrows (>>) for the second pair. The two lines below would be labeled AB←→ || MN←→− or l || m.

For a line and a point not on the line, there is exactly one line parallel to this line through the point. There are infinitely many lines that pass through A, but only one is parallel to l.

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3 years ago

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Simplifying Rational Expressions

Evgen [1.6K]

B^-2 / b^-3 = b^(-2-(-3) = b^1 = b

answer is d

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3 years ago

Determine whether Point A lies on the circle whose center is Point C and whichcontains the Point P. Justify your answer mathemat

Arada [10]

The Solution:

Given:

Center = (0,0)

Point A = (-5,2) being a point on the circle.

We are required to check if point P = (2,-5) is on the circle.

Solving the given problem graphically, we have:

From the above graph, it is clear that point P(2,-5) is a point on the circle.

8 0

1 year ago

Suppose that in a large metropolitan area, 84% of all households have cable tv. Suppose you are interested in selecting a group

Firdavs [7]

Answer:

0.05606

Step-by-step explanation:

This is a binomial probability distribution problem.

84% of all households have cable TV, thus;

p = 0.84

There are six households from this area, thus; n = 6

Formula for this binomial distribution is;

P(X) = C(n, x) × p^(x) × (1 - p)^(n - x)

We want to find the proportion of groups where at most three of the households have cable TV.

Thus, it's is;

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = 0) = C(6, 0) × 0.84^(0) × (1 - 0.84)^(6 - 0) = 0.00001678

P(X = 1) = C(6, 1) × 0.84^(1) × (1 - 0.84)^(6 - 1) = 0.000528

P(X = 2) = C(6, 2) × 0.84^(2) × (1 - 0.84)^(6 - 2) = 0.006963

P(X = 3) = C(6, 3) × 0.84^(3) × (1 - 0.84)^(6 - 3) = 0.04855

Thus;

P(X ≤ 3) = 0.00001678 + 0.000528 + 0.006963 + 0.04855 = 0.05606

5 0

3 years ago