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Elodia [21]
3 years ago
14

- IZ

Mathematics
1 answer:
Yakvenalex [24]3 years ago
3 0

Step-by-step explanation:

Subtract initial amount (300) and final (150). from there you get 150 dollars that was lost. We know that every step you 5 dollars so then divide 150 and 5 to get 30. So the distance was 30 steps.

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What is the Y- intercept of the graph of the line given by equation 3y+4x=15?
KATRIN_1 [288]
Yint is where the line crosses the y axis or where x=0
set x=0

3y+4x=15
x=0
3y+4(0)=15
3y+0=15
3y=15
divide by 3
y=5

yint is (0,5) or at y=5
3 0
3 years ago
What is the answer to -4(5x6)
Softa [21]
<span>-4(5x6)
=</span><span>-4(30)
= - 120</span>
8 0
3 years ago
The population of a city grows exponentially at rate of 8% per year.Find the number of years it takes for the population to be d
Ilya [14]

Answer:

<em>It will take 9 years for the population to double</em>

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

P=P_o(1+r)^t

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

The population of a city grows at a rate of r=8% = 0.08 per year. We are required to find when (t) the population will double, or P=2Po.

Substituting in the equation:

2P_o=P_o(1+0.08)^t

Simplifying:

2=(1.08)^t

Taking logarithms:

\log 2=\log (1.08)^t

Applying the exponent property of logs:

\log 2=t\log (1.08)

Solving for t:

\displaystyle t=\frac{\log 2}{\log (1.08)}

Calculating:

t\approx 9

It will take 9 years for the population to double

8 0
2 years ago
Follow the process of completing the square to solve 2x2 + 8x - 12 = 0. After adding B2 to both sides of the equation in step 4,
valentina_108 [34]
 2x2 + 8x - 12 = 0
4 + 8x - 12 = 0
8x = 12 - 4
8x = 8
x = 1
4 0
3 years ago
Express 82 kilometers per hour in miles per hour
mezya [45]

Step-by-step explanation:

a)82km into miles

Sol'n

Here,

km=82=82000miles

m=?

Now,

Miles =km×1000

=82×1000

=82000

Therefore,82000m.

6 0
3 years ago
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