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Elodia [21]
3 years ago
14

- IZ

Mathematics
1 answer:
Yakvenalex [24]3 years ago
3 0

Step-by-step explanation:

Subtract initial amount (300) and final (150). from there you get 150 dollars that was lost. We know that every step you 5 dollars so then divide 150 and 5 to get 30. So the distance was 30 steps.

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Colin pays £721.45 a year on his car insurance.
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655.08

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<h3>721.45 ×0.092=66.3734</h3><h3>721.45-66.3734=655.0766</h3>
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Solve the following equation.<br> 3 ( w + 5) = 2 ( 3w + 12)
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2 years ago
Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}
miskamm [114]

Answer:

-3+i\sqrt{3} , 1+\sqrt{3}

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

\alpha = x+iy\\\beta = x-iy

since they are conjugates

\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}

\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}

Imaginary part of the above =0

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So the value of alpha = -3+i\sqrt{3} , 1+\sqrt{3}

3 0
3 years ago
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