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k0ka [10]
3 years ago
11

A 0.010 kg clay ball thrown right at 16 m/s hits a marble moving left at 8.0 m/s, and sticks to it. Both move left at 3.2 m/s af

ter the collision. What is the mass of the marble?
Physics
2 answers:
4vir4ik [10]3 years ago
7 0

Answer:

0.040

Explanation:

Anettt [7]3 years ago
6 0
.……… it will be 7.5m/s
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Through what angle in degrees does a 33 rpm record turn in 0.32 s?<br> 63°<br> 35°<br> 46°<br> 74°
Darina [25.2K]

Answer:

1 rev = 2(pi) rad  pi(rad) = 180 degrees

so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees

Explanation:

63.36 estimated to 63 so 63

6 0
3 years ago
If I work out rotational energy to be 102.2J which equals kg.M/s^2, and I hadn't factored time into it, would that be Joules per
Marina CMI [18]

Answer:

0.057 joules is needed to create the total rotational energy each second.

Explanation:

The energy rate is the ratio of total energy to time, which coincides with the definition of power at constant rate:

\dot W = \frac{\Delta E}{\Delta t}

\dot W = \frac{102.2\,J}{\left(30\,min\right)\cdot \left(60\,\frac{s}{min} \right)}

\dot W = 0.057\,\frac{J}{s}

\dot W = 0.057\,W

0.057 joules is needed to create the total rotational energy each second.

7 0
3 years ago
A sanding disk with rotational inertia 1.2 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of 10 N·m a
tensa zangetsu [6.8K]

Answer:

Angular momentum = 0.7 kg.m²/s

Angular velocity = 583.3 rad/s

Explanation:

1. The torque τ  is related to the angular momentum L by the relation

τ = ΔL/Δt

ΔL = τΔt

τ = 10 N. m

Δt = 70 ms = 70 × 10⁻³s

ΔL = (10 N. m) × (70 × 10⁻³s) = 700 × 10⁻³ kg.m²/s = 0.7 kg.m²/s

2. The rotational inertia I relates the angular momentum L to the angular velocity w

L = Iw

w = L/I

L =  0.7 kg.m²/s

I = 1.2 × 10⁻³ kg.m²

w = (0.7 kg.m²/s)/(1.2 × 10⁻³ kg.m²) = 583.3 rad/s

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yanalaym [24]
The answer is convection
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Matter is __________.
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3 years ago
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