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2 years ago

15

What human process are carbon sources that are upsetting the balance between CO to update via planets and CO2 released by living

things?

1 answer:

Serhud [2]2 years ago

5 0

The combustion of fossil fuels is releasing more co2 into the atmosphere then what would occur naturally

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The membrane that surrounds a certain type of living cell has a surface area of 5.1 x 10-9 m2 and a thickness of 1.4 x 10-8 m.

ziro4ka [17]

a) The charge on the outer surface is $1.2\cdot 10^{-12} C$

b) The number of ions is $7.5\cdot 10^6$

Explanation:

a)

The membrane behaves as a parallel plate capacitor, whose capacity is given by the equation

$C=\frac{k\epsilon_0 A}{d}$

where

k = 4.3 is the dielectric constant

$\epsilon_0 =8.85\cdot 10^{-12} F/m$ is the vacuum permittivity

$A=5.1\cdot 10^{-9} m^2$ is the surface area

$d=1.4\cdot 10^{-8} m$ is the distance between the two plates

Substituting,

$C=\frac{(4.3)(8.85\cdot 10^{-12})(5.1\cdot 10^{-9})}{1.4\cdot 10^{-8}}=1.4\cdot 10^{-11} F$

The capacity of the membrane is related to the potential difference between the two surfaces by

$C=\frac{Q}{\Delta V}$

where here we have

Q = excess charge on one surface

$\Delta V = 85.5 mV = 0.0855 V$ is the potential difference between the two surfaces

Solving for Q, we find

$Q=C\Delta V=(1.4\cdot 10^{-11})(0.0855)=1.2\cdot 10^{-12} C$

b)

We said that the net charge on the outer surface is

$Q=1.2\cdot 10^{-12} C$

The charge of one K+ ions is equal to the electron charge

$+e=1.6\cdot 10^{-19} C$

Therefore, the number of ions on the outer surface can be found by dividing the total charge by the charge of a single ion:

$N=\frac{Q}{e}=\frac{1.2\cdot 10^{-12}}{1.6\cdot 10^{-19}}=7.5\cdot 10^6$

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6 0

3 years ago

____ can lift the 403,342 ton pioneering spirit crane vessel 10 meters in 30 seconds as if it was a cork. This about 36 GJ if wo

azamat

Answer: <u>Trough </u> can lift the 403,342 ton pioneering spirit crane vessel 10 meters in 30 seconds as if it was a cork. This about 36 GJ if work and 1 GW of power.

Explanation:

Why trough?

Trough is the correct answer because<u> pioneering scale usually abide only on trough not on the other given options</u>. A long , narrow depression between the waves or ridges is known as a trough. The lower point in the period is the trough.

<u>Speed -:</u> Speed is the distance per unit of time that a body moves. It's a quantity scaler that has just magnitude.
<u>Wave energy -: </u>The transmission and capture of energy by ocean surface waves is wave energy (or wave power). The energy collected is then used for all sorts of useful work, including the generation of electricity, water desalination, and water pumping.
<u>Crest -</u>: A crest point within a cycle on a wave with the highest value of upward displacement. A crest is a point on a surface wave where the medium's displacement is at its height.
<u>Amplitude -:</u> The maximum displacement or distance measured from its equilibrium position, moved by a point on a vibrating body or wave, is called amplitude. It is equal to half of the vibration path's length.
<u>Period-</u>: The duration T is the time needed to pass a given point for one complete cycle of vibration. The wave length decreases as the frequency of a wave increases.
<u>Wavelength-:</u> The distance between two successive crests or troughs of a wave can be described as the wavelength. The frequency is inversely proportional to the wavelength. This implies that the longer the wavelength, the smaller the frequency. Similarly, the shorter the wavelength, the higher the frequency would be.
<u>Frequency</u> -: Frequency defines the number of waves in a given amount of time that travel through a fixed location. In the Hertz unit, frequency is normally measured.
<u>Information</u> -: A piece of data is a basic fact about the identity or properties of an object, i.e. a portion of its example.
<u>Milli -</u>: Milli is known as a merged form meaning 'thousand' (millipede) used in the metric system for unit names equal to one thousandth of the base unit (millimeter) given.

Hence , the answer is <u>TROUGH.</u>

7 0

3 years ago

A 9 volt battery produces a current of 0.2A. What is the resistance?

nekit [7.7K]

9/0.2 would be the ans

4 0

3 years ago

The base of a pyramid covers an area of 13.0 acres (1 acre = 43,560 ft2) and has a height of 481 ft. If the volume of a pyramid

Allisa [31]

V = 1/3 Bh v = 1/3 (13 ac)(43560ft^2/ac)(481ft) v = 90793560 ft^3 * 0.3048m/ft * 0.3048m/ft * 0.3048m/ft = 2570987m^3

3 0

3 years ago

Read 2 more answers

2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or

krek1111 [17]

a) The work done by the tree is $-1.44\cdot 10^5 J$

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

$W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2$

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

$W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J$

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

$W=Fd$

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

$W=-1.44\cdot 10^5 J$ is the work done

$d=50.0 cm = 0.50 m$ is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

$F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N$

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

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3 0

3 years ago