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2 years ago

What would happen if scientists dis not communicate

Physics

2 answers:

erica [24]2 years ago

5 0

If scientists do not communicate, information is not shared, but more importantly, it is not verified.

VladimirAG [237]2 years ago

3 0

There would be so many explanations of how things work and no one would know which ones are right.

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Where does these choices go?

murzikaleks [220]

Answer:

Nothing goes to Kinetic Energy

Both-1, 2, 4

Potential Energy-3 and 5

Explanation:

6 0

2 years ago

A student weighing 700 N climbs at constant speed to the top of an 8 m vertical rope in 10 s. The average power expended by the

nasty-shy [4]

Answer:

The average power the student expended to overcome gravity is 560W, Watts is a units of work it is Joules /time or kg* $m^{2}$ / $s^{3}$

Explanation:

Weight = 700N

$F= m*g*h \\m*g= 700N\\F= 700N*h\\F=700N*8m\\F= 5600 N*m \\F=5600 J$

The power is the work in (Joules) or (N*m) in a determinate time (s) to get Watts (W) units for work

$Work= \frac{5600 J}{10s} = \frac{5600 \frac{kg*m^{2} }{s^{2} } }{10 s} \\Work= 560\frac{kg*m^{2} }{s^{3} } \\Work =560 W$

3 0

2 years ago

What are 2 ways organisms would be affected by water pollution?

Ymorist [56]

Not having clean water to drink or bath. Also some organizations that live in the water might die because the water is polluted and that would be toxic form them

7 0

3 years ago

Which statement best describes the direction of the buoyant force on any object?

poizon [28]

The buoyant force on any object acts in the direction opposite to the force of gravity. <em>(A)</em>

5 0

2 years ago

Read 2 more answers

The electric field everywhere on the surface of a thin, spherical shell of radius 0.770 m is of magnitude 860 N/C and points rad

11111nata11111 [884]

Answer:

(a) $Q = 7.28\times 10^{14}$

(b) The charge inside the shell is placed at the center of the sphere and negatively charged.

Explanation:

Gauss’ Law can be used to determine the system.

$\int{\vec{E}} \, d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E4\pi r^2 = \frac{Q_{enc}}{\epsilon_0}\\(860)4\pi(0.77)^2 = \frac{Q_{enc}}{8.8\times 10^{-12}}\\Q_enc = 7.28\times 10^{14}$

This is the net charge inside the sphere which causes the Electric field at the surface of the shell. Since the E-field is constant over the shell, then this charge is at the center and negatively charged because the E-field is radially inward.

The negative charge at the center attracts the same amount of positive charge at the surface of the shell.

5 0

3 years ago