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andreev551 [17]
3 years ago
9

What would happen if scientists dis not communicate

Physics
2 answers:
erica [24]3 years ago
5 0
If scientists do not communicate, information is not shared, but more importantly, it is not verified.
VladimirAG [237]3 years ago
3 0
There would be so many explanations of how things work and no one would know which ones are right.
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"A 0.4 kg mass, attached to the end of a 0.75 m string, is whirled around in a circular horizontal path. If the maximum tension
Nimfa-mama [501]

Answer:

The maximum velocity the mass can have if the string is not to break = 29.05 m/s

Explanation:

The force balance in the mass:

The tension in the string must always be equal to the force keeping the mass in horizontal circular motion.

The force keeping the mass in circular motion is given by

F = mv²/r

m = mass of body = 0.4 kg

v = speed of the body in circular motion

r = radius of the circular motion = 0.75 m

Maximum tension the string can withstand will correspond to the maximum velocity of the body in horizontal circular motion

T = F = mv²/r

450 = (0.4)(v²)/(0.75)

v² = 450×0.75/0.4 = 843.75

v = 29.05 m/s

4 0
3 years ago
Read 2 more answers
A positive charge of 18nC is evenly distributed along a straight rod of length 4.0 m that is bent into a circular arc with a rad
sergey [27]

Explanation:

Formula for angle subtended at the center of the circular arc is as follows.

           \theta = \frac{S}{r}

where,   S = length of the rod

              r = radius

Putting the given values into the above formula as follows.      

                \theta = \frac{S}{r}

                             = \frac{4}{2}

                             = 2 radians (\frac{180^{o}}{\pi})

                             = 114.64^{o}

Now, we will calculate the charge density as follows.

                 \lambda = \frac{Q}{L}

                            = \frac{18 \times 10^{-9} C}{4 m}

                            = 4.5 \times 10^{-9} C/m

Now, at the center of arc we will calculate the electric field as follows.

                 E = \frac{2k \lambda Sin (\frac{\theta}{2})}{r}

                     = \frac{2(9 \times 10^{9} Nm^{2}/C^{2})(4.5 \times 10^{-9}) Sin (\frac{114.64^{o}}{2})}{2 m}

                      = 34.08 N/C

Thus, we can conclude that the magnitude of the electric eld at the center of curvature of the arc is 34.08 N/C.

5 0
3 years ago
Gravity on Earth is 9.8 m/s2, and gravity on Mars is 3.7 m/s2.
antiseptic1488 [7]
W = mg

Weight on Earth = 50 x 9.8
                          = 490 N

Weight on Mars = 50 x 3.7
                          = 185 N 
8 0
3 years ago
Read 2 more answers
PLZ HELP
Goshia [24]
Space debris that enters earths atmosphere
5 0
3 years ago
In the simulation above, as the projectile travels upward, how does the vertical velocity change? Question 9 options:
enot [183]

Answer:

Vertical velocity decreases.

Explanation:

The motion of the ball is a projectile ball, which consists of two independent motions:

- a horizontal motion, with constant velocity

- a vertical motion, with constant acceleration g=9.8 m/s^2 towards the ground

In the vertical motion, there is a constant acceleration directed downward: this means that the vertical velocity decreases as the ball goes higher. In fact, it decreases following the equation

v(t)=v_0 -gt

And it decreases until the ball reaches its maximum height, then it starts increasing again.

4 0
3 years ago
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