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Bad White [126]
3 years ago
6

What is the distance between (12,12) (-12,-12)

Mathematics
1 answer:
katrin [286]3 years ago
4 0

Answer:

24\sqrt{2} or 33.94112

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

d = \sqrt{(x_{2} -x_{1})^{2} + (y_{2} - x_{1})^{2}  }

d = distance

(x_{1}, y_{1}) = coordinates of the first point

(x_{2}, y_{2}) = coordinates of the second point

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Verdich [7]

Answer: 9 over 12 is = 15 over x

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What is 14/100 simplified
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7/50 is your answer

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two boats leave the jetty at the same time. one of them returns to the jetty every 25 minutes and the second one returns every 3
mars1129 [50]

Answer:

150 mins or 2 hrs 30 mins

Step-by-step explanation:

This is simply the LCM ( lowest common multiple)

therefore, you find all the prime factors of 25 using a tree diagram resulting in 5^2 and 30 which will be 2 x 3 x 5. Then you multiply all the factors together and you will get 5 x 5 x 2 x 3 = 150

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the answer is after 150 mins

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3 years ago
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Harold spent 3/4 hour milking cows. He milked 3 groups of cows. If he spent an equal amount of time on each group of cows, what
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(3/4)/3

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5 0
3 years ago
A tire manufacturer wants to estimate the average number of miles that may be driven in a tire of a certain type before the tire
alexandr402 [8]

Answer:

97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

Step-by-step explanation:

We are given that a random sample of tires is chosen and are driven until they wear out and the number of thousands of miles is recorded;

32, 33, 28, 37, 29, 30, 22, 35, 23, 28, 30, 36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                                P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average number of miles = \frac{\sum X}{n} = 30.25

            s  = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} } = 4.71

            n = sample of tires = 12

            \mu = population average number of miles

<em>Here for constructing a 97% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<u>So, 97% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.55 < t_1_1 < 2.55) = 0.97  {As the critical value of t at 11 degrees of

                                              freedom are -2.55 & 2.55 with P = 1.5%}  

P(-2.55 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.55) = 0.97

P( -2.55 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.55 \times {\frac{s}{\sqrt{n} } } ) = 0.97

P( \bar X-2.55 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.55 \times {\frac{s}{\sqrt{n} } } ) = 0.97

<u>97% confidence interval for</u> \mu = [ \bar X-2.55 \times {\frac{s}{\sqrt{n} } } , \bar X+2.55 \times {\frac{s}{\sqrt{n} } } ]

                                        = [ 30.25-2.55 \times {\frac{4.71}{\sqrt{12} } } , 30.25+2.55 \times {\frac{4.71}{\sqrt{12} } } ]

                                        = [26.78 miles, 33.72 miles]

Therefore, 97% confidence interval for the average number of miles that may be driven is [26.78 miles, 33.72 miles].

7 0
4 years ago
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