Answer:
The length is 7.50metres and the width is 5metres
Explanation:
Given the following
Length = 1.5Width
Perimeter = 25m
Required
Dimension of the room
Perimeter of the rectangular room = 2(L+W)
Since L = 1.5W
P = 2(1.5W+W)
P = 2(2.5W)
P = 5.0W
25 = 5W
W = 25/5
W = 5metres
Since L = 1.5W
L = 1.5*5
L = 7.5meters
The length is 7.50metres and the width is 5metres
Answer:
l = 23 cm and w = 5.7 cm
Step-by-step explanation:
Perimeter = twice the length plus twice the width
let w = width
let l = length
l = 5.9 + 3w
57.4 = 2(5.9 + 3w) + 2w
57.4 = 11.8 + 6w + 2w
57.4 = 11.8 + 8w
45.6 = 8w
w = 5.7
Substitute 5.7 for 'w' to get 'l':
l = 5.9 + 3(5.7)
l = 23
X= -9.375. 0.06x-0.14x=13.48-12.73. -0.08x=0.75
Awnser: y=1
Distribute
6=2(y+2)
6=2y+4
subtract 4 from both sides of the equation
6=2y+4
6-4=2y+4-4
simply
2=2y
then divide 2 from both sides
2/2=2y/2
y=1
Hope this helps :)
if x is the bigger num and y is the smaller
x + y = 91
x - 3y = 7.7
multiply by -1
x+y = 91
-x + 3y = -7.7
add the equations
4y = 91 - 7.7
4y = 83.3
y = 20.825
then x+y = 91 use to find x
x+20.825 = 91
x = 70.175
the two numbers are 70.175 and 20.825
