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xz_007 [3.2K]
3 years ago
14

Determine the solution to the system. Explain students steps to solving the systems of equations.

Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0
<h2><u>QUESTION</u><u>:</u></h2>

Determine the solution to the system. Explain students steps to solving the systems of equations.

  • A).-1
  • B).3
  • C).(-1,3)
  • D).(3,-1)

\\

\\

\Large{\underline{\mathcal{Given:}}}

<u>ᴇǫᴜᴀᴛɪᴏɴs</u><u>:</u>

1️⃣➤x -4y = 7

2️⃣➤5x + 9y = 6

\\

\\

\Large{\underline{\mathcal{ToFind:}}}

x and y values .

\\

\\

\Large{\underline{\mathcal{Solution:}}}

\\

\\

➠Here the elimination method is used as it is in the form of

<h2> <u> </u><u> </u><u>Ɑx + Ɓყ = Ƈ</u> , </h2>

where the two variables are unknown

\\

\\

➠<em>The two equations are added or subtracted to get one unknown value and later the identified value is substituted in either of the equation in order to get the another unknown value</em>

\\

<u>ʙʏ ᴇʟɪᴍɪɴᴀᴛɪᴏɴ ᴍᴇᴛʜᴏᴅ</u><u> </u><u>:</u>

1️⃣➤x -4y = 7

2️⃣➤5x + 9y = 6

\\

➠First equation is multiplied with the suitable number in order to get any of the x or y values cancelled

then,

\\

\\

1️⃣ ×-5➤-5x +20y = -35

2️⃣ ➤ 5x +9y = 6

___________________

\:\:\:➺29y = -29

\:\:\:➺y =- 29/29

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underline{\boxed{\sf{ y =  \frak{\pink{-1}}}}}

\\

\\

Now,

\\

\\

➠ the identified value is substituted in either of the equation in order to get the another unknown value

\\

\\

1️⃣➤x -4y = 7

\:\:\:➺x - 4(-1) = 7

\:\:\:➺x +4 = 7

\:\:\:➺x = 7-4

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underline{\boxed{\sf{ x = \frak{\red{3}}}}}

____________________________

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sung buys a 12-month membership to a gym there is no sign up fee and sung makes equal payments each month after three months he
Nataly [62]

The solution is

a) The amount Sung pays per month is $ 65

b) The total amount for the 12-month memberships is $ 780

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the total amount of the 12-month membership fee be represented as A

Now , the value of A is

The amount balance after 3 months = $ 585

The amount balance after 5 months = $ 455

So ,

The difference between the months = 5 months - 3 months

The difference between the months = 2 months

The difference between the amounts = $ 585 - $ 455

The difference between the amounts = $ 130

So , for the period of 2 months , the amount = $ 130

The amount for 1 month of the membership = $ 130 / 2

The amount for 1 month of the membership = $ 65

Now , the equation will be

Total amount of the 12-month membership fee A = 12 x amount for 1 month of the membership

Substituting  the values in the equation , we get

Total amount of the 12-month membership fee A = 12 x $ 65

Total amount of the 12-month membership fee A = $ 780

Therefore , the value of A is $ 780

Hence ,

The total membership amount is $ 780 and amount per month is $ 65

To learn more about equations click :

brainly.com/question/19297665

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3 0
1 year ago
101/25converted to a mixed number
elena55 [62]
101÷25
4 with a remainder of 1/25
4 1/25
6 0
3 years ago
How are slopes and y intercepts to the number of solutions of a system of the liner
Leona [35]
We assume a linear system with 2 variables.


If the slopes are the same, and y-intercepts are different, there are 0 solutions.

If the slopes are different, there is 1 solution.

If the slopes are the same, and the y-intercepts are the same, there are ∞ solutions.
7 0
4 years ago
Sec^4x-tan^4x=sec^2x+tan^2x
tino4ka555 [31]
\sec^4x-\tan^4x=(\sec^2x-\tan^2)(\sec^2x+\tan^2x)=\sec^2x+\tan^2x

since \tan^2x+1=\sec^2x.
5 0
3 years ago
If f ( x ) = x^4 + 4 , g ( x ) = x − 6 , h ( x ) = √ x , then f ∘ g ∘ h ( x ) =
yanalaym [24]

Answer:

f(g(h(x))) = (\sqrt{x} -6)^4 +4

Step-by-step explanation:

Given:

f(x) = x^4 +4

g(x) = x -6

h(x) = \sqrt{x}

Solution:

f°g°h(x) = f(g(h(x)))

We can solve for g(h(x)) to make it less complicated.

g(h(x)) = h(x) -6 \\ g(h(x)) = \sqrt{x} -6

Now we can solve for f(g(h(x))).

f(g(h(x))) = g(h(x))^4 +4 \\ f(g(h(x))) = (\sqrt{x} -6)^4 +4

5 0
3 years ago
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