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Zarrin [17]
3 years ago
13

How do you solve the equation 2cos^2 - cosx = 0 for all solutions?

Mathematics
1 answer:
exis [7]3 years ago
7 0

Answer:

<em>π/2 and π/3</em>

Step-by-step explanation:

Given the equation 2cos²x - cosx = 0, to find the solution to the equation, we will follow the following step.

let P = cosx

The equation becomes 2P²-P = 0

P(2P-1) = 0

P = 0 and 2P-1 = 0

P= 0 and P = 1/2

Since P = cosx

cosx = 0 and cos(x) =  1/2

If cos(x) = 0

x = cos⁻¹0

x = 90⁰

x = π/2

If cos(x) = 1/2

x = cos⁻¹1/2

x = 60⁰

x = π/3

<em>Hence the solutions to the equation are π/2 and π/3.</em>

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Ok this is a very question that can solved very easily. So we know that there three numbers, and they are consecutive, this means that they are all one bigger than the number before so for example 1,2, and 3 or 20, 21, and 22. These numbers are called consecutive. Now let's just pretend that the answer to this question is the variable "x". Now x is the smallest number in all the three numbers.

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