Answer:
Option B. The planet is a very way from the center or the Sun.
Explanation:
If the surface temperature of the newly formed planet is - 20 K that means the distance of the planet from the sun in greater.
If we look at the temperature trends of the planets in our solar system, the planets closer to the sun like Mercury, Venus have very high surface temperature but as we move move away from the the center of the solar system, i.e., Sun, the temperature goes on decreasing.
s=600 m
t=12 s
s=0.5*a*t² (initial speed V0=0)
a=(2*s)/t²
a=(2*600)/12²
a≈8.33 m/s²
L= s(t2=12s)-s(t1=11s) -> (distance during the twelfth second)
L=0.5*a*(t2²-t1²)
L=0.5*((2*s)/t²)*(t2²-t1²)
L=0.5*((2*600)/12²)*(12²-11²)
L ≈ 95.83 m
Answer:
Explanation:
Step one:
given data
initial velocity u= 40m/s
time taken t=3seconds
final velocity v=?
Step two:
applying the first equation of motion
v=u-gt--- (the -ve sign implies that the arrow is against gravity)
assume g=9.81m/s^2
v=40-9.81*3
v=40-29.43
v=10.57m/s
Step three:
how high the target is located
applying
s=ut-1/2gt^2
s=40*3-1/2(9.81)*3^2
s=120-88.29/2
s=120-44.145
s=75.86m
Static electric fields are caused by charged particles when the atoms which compose the particle will have the same number of electrons as protons.
Each point in space has an electric field associated with it when the charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.
Both the electromagnetic wave produced by a radio broadcast monopole antenna and the field created in the dielectric of a parallel-plate capacitor are examples of electric fields (which create a time-varying field). Every place in space where a charge, regardless of its shape, is present is said to have an electric field, which is an electric attribute. The electric field's equation is given as E = F / Q.
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Writing the acceleration as a function of time:
a(t) = 1 + 3√t
Integrating acceleration, we obtain velocity:
v(t) = t + 2(t)^(3/2) + c;
object at rest so velocity at t = 0 is 0 so c = 0.
v(t) = t + 2(t)^(3/2)
Integrating velocity to obtain an equation for displacement:
d(t) = t²/2 + 4/5 t^(5/2) + c
Applying limits from t = 0 to t = 9
d = 9²/2 + 4/5 9^(5/2)
d = 234.9 m
