Answer:
L= 2 mH
Explanation:
Given that
Frequency , f= 10 kHz
Maximum current ,I = 0.1 A
Maximum energy stored ,E= 1 x 10⁻⁵ J
The maximum energy stored in the inductor is given as follows
Where ,L= Inductance
I=Current
E=Energy
Now by putting the values in the above equation
L=0.002 H
L= 2 mH
We know that frequency f is given as
C=Capacitance , f=frequency ,L=Inductance
Now by putting the values
Therefore the inductance and capacitance will be 2 mH and 1.26 x 10⁻⁷ F respectively.
The correct answer is D He could pull the mass down farther.
Amplitude, is the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. So to increase the amplitude the spring should be pulled down further which can increase the amplitude.
Answer:
x=0.154kg
Explanation:
(x*L)+(0.5kg*4200*50)+(x*4200*(-50)=0
(x*333 000J/kg*c)+(0.5kg*4200J/kg*C*(-40C))+(x*4200J/kg*C*50C)=0
To get a uniform field in the central region between the coils, current flows in the same direction in each.
