HI, I really need help with this assignment for Physics:

The average distance an electron travels between collisions is 2.0 μmμm . What acceleration must an electron have to gain 2.0×10

Ilya [14]

The solution is in the attachment

4 0

2 years ago

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A 4 kg bird is flying with a velocity of 4 m/s. What is its kinetic energy?

Maslowich

32 kg m/s would be the kinetic energy.

3 0

2 years ago

A severe thunderstorm, known as a supercell, forms. It begins in an area where cold, dry, polar air meets warm, moist, tropical

alexdok [17]

Answer:

A tornado can, surprisingly, cause a supercell, so the answer would be C.) tornado

Explanation:

When cold, dry, and polar air meet warm, moist tropical air, the atmosphere becomes unstable causing a supercell.

Final Answer:

C.) tornado

Afterthought:

Please give BRAINLEST!

Thanks,

-johannelbekian

8 0

2 years ago

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A woman is standing in the ocean, and she notices that after a wavecrest passes, five more crests pass in a time of 50.0 s. Thed

Vadim26 [7]

Answer:

(a) T = 10 s

(b) f = 0.1 Hz

(c) λ = 32 m

(d) v = 3.2 m/s

(e) Insufficient data

Explanation:

(a)

Time period is defined as the time interval required for one wave to pass. Therefore, the time period can be given as:

T = Period = Time Taken/No. of Waves

T = 50 s/5

T = 10 s

(b)

Frequency is the reciprocal of time period:

f = frequency = 1/T

f = 1/10 s

f = 0.1 Hz

(c)

Wavelength is the distance between two consecutive crests or troughs:

λ = Wavelength = 32 m

(d)

Speed of wave is given by the following formula:

Speed = v = fλ

v = (0.1 Hz)(32 m)

v = 3.2 m/s

(e)

Amplitude cannot be found with given data.

6 0

2 years ago

10. How far does a transverse pulse travel in 1.23 ms on a string with a density of 5.47 × 10−3 kg/m under tension of 47.8 ?????

KATRIN_1 [288]

Answer: Tension = 47.8N, Δx = 11.5× $10^{-6}$ m.

Tension = 95.6N, Δx = 15.4× $10^{-5}$ m

Explanation: A speed of wave on a string under a tension force can be calculated as:

$|v| = \sqrt{\frac{F_{T}}{\mu} }$

$F_{T}$ is tension force (N)

μ is linear density (kg/m)

Determining velocity:

$|v| = \sqrt{\frac{47.8}{5.47.10^{-3}} }$

$|v| = \sqrt{0.00874 }$

$|v| =$ 0.0935 m/s

The displacement a pulse traveled in 1.23ms:

$\Delta x = |v|.t$

$\Delta x = 9.35.10^{-2}*1.23.10^{-3}$

Δx = 11.5× $10^{-6}$

With tension of 47.8N, a pulse will travel Δx = 11.5× $10^{-6}$ m.

Doubling Tension:

$|v| = \sqrt{\frac{2*47.8}{5.47.10^{-3}} }$

$|v| = \sqrt{2.0.00874 }$

$|v| = \sqrt{0.01568}$

|v| = 0.1252 m/s

Displacement for same time:

$\Delta x = |v|.t$

$\Delta x = 12.52.10^{-2}*1.23.10^{-3}$

$\Delta x =$ 15.4× $10^{-5}$

With doubled tension, it travels $\Delta x =$ 15.4× $10^{-5}$ m

4 0

2 years ago