Answer: Hello, 6
Therefore, the tenths value of 3.629 remains 6. The following table contains starting numbers close to 3.629 rounded to the nearest 10th.
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Step-by-step explanation:
Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
Answer:
is that the whole question? I think it is missing something. Send a picture of it if you can.
Step-by-step explanation:
Perimeter of rec. = 2 ( l + w )
Given: perimeter of rectangle = 322m, length = 86m
Required: width = ?
Solution: 322 = 2 ( 86 + w )
Divide 322 by 2 ie, 322/2 = 86 + w
Will be equal to 161 = 86 + w
Therefore Width= 161 - 86 = 75
Step-by-step explanation:
hope this helps you.........