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Rus_ich [418]
3 years ago
7

the perimeter of a rectangle parking lot is 322 m. if the length of the parking lot is 86 m, what is the width

Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0
Perimeter of rec. = 2 ( l + w )

Given: perimeter of rectangle = 322m, length = 86m

Required: width = ?

Solution: 322 = 2 ( 86 + w )
Divide 322 by 2 ie, 322/2 = 86 + w
Will be equal to 161 = 86 + w
Therefore Width= 161 - 86 = 75

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Find the coordinates of the other endpoint when given midpoint (point M) and one of the endpoints (point P). P=(3,5) and M=(-2,0
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About Points

S = (x,y)        searched point (it will be in the third quadrant )

M = (-2,0)      Midpoint | SP |

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You have to draw Cartesian.

we set in a point M and P. We both points by a simple and we extend it for the third quarter of the system. Compass measure the distance from the point M to the point P. From the point M we set a compass point S. Figure attached. Received point S = ( -7 , -5 ) . It sought a point that calculate .

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8 0
3 years ago
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ASAP The rectangle below has been enlarged by a scale of 3.5. A rectangle with a length of 8 and width of 6. [Not drawn to scale
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Answer:

588 units^2

Step-by-step explanation:

To find the area of the enlarged rectangle, first find the length and width of the enlarged rectangle.

This is 3.5 multiplied by their original measures:

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