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3 years ago

the perimeter of a rectangle parking lot is 322 m. if the length of the parking lot is 86 m, what is the width

1 answer:

4 0

Perimeter of rec. = 2 ( l + w )

Given: perimeter of rectangle = 322m, length = 86m

Required: width = ?

Solution: 322 = 2 ( 86 + w )
Divide 322 by 2 ie, 322/2 = 86 + w
Will be equal to 161 = 86 + w
Therefore Width= 161 - 86 = 75

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saw5 [17]

Answer:

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Step-by-step explanation:

Given

$A = (2,6)$

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$C = (8,6)$

Required

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The coordinate point of a horizontal or a vertical rectangle is given as:

(x1,y1), (x2,y2), (x3,y3), (x4,y4)

Where:

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So, we have:

$A = (2,6)$ --- $(x_1.y_1)$

$B = (2,9)$ ---- $(x_2.y_2)$

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Using the above equations:

$x_3 = x_4$ $=8$

$y_2 = y_4$ $= 9$

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3 years ago

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Amiraneli [1.4K]

Answer:

$\boxed{D. \: 40\degree}$

Step-by-step explanation:

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So,

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Step-by-step explanation:

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Read 2 more answers

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dmitriy555 [2]

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Step-by-step explanation:

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3 years ago