the perimeter of a rectangle parking lot is 322 m. if the length of the parking lot is 86 m, what is the width

1 answer:

4 0

Perimeter of rec. = 2 ( l + w )

Given: perimeter of rectangle = 322m, length = 86m

Required: width = ?

Solution: 322 = 2 ( 86 + w )
Divide 322 by 2 ie, 322/2 = 86 + w
Will be equal to 161 = 86 + w
Therefore Width= 161 - 86 = 75

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