the perimeter of a rectangle parking lot is 322 m. if the length of the parking lot is 86 m, what is the width
1 answer:
Perimeter of rec. = 2 ( l + w )
Given: perimeter of rectangle = 322m, length = 86m
Required: width = ?
Solution: 322 = 2 ( 86 + w )
Divide 322 by 2 ie, 322/2 = 86 + w
Will be equal to 161 = 86 + w
Therefore Width= 161 - 86 = 75
You might be interested in
Answer: x=1/384
Step-by-step explanation: Hope this help :D
Answer:
9
Step-by-step explanation:
Answer:
x = -11
Step-by-step explanation:
Because 3 x -11 = -33 and
8 -(-33 = 41
Yes, you can use The Law of Cosines to find the angles
Answer:
(x-5)²+(y+7)²=36
or
x²+y²-10x+14y+38=0