X - 9 - -2 — x - 2 Solve for all values of x.

Which ordered pair is the solution to the system of linear equations y=5x+8 and -4x-1 ?

Margarita [4]

Hello :

y=5x+8
y= -4x-1
5x+8 = -4x-1
9x =-9
x = -1
y = 5(-1)+8 = 3
ordered pair is the solution to the system : ( -1 , 3)

8 0

3 years ago

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I NEED HELP can. someone help me please

Andrej [43]

Answer:

A & E

10-11= - 1

4y-5y= - y

4x5=20

4 x 2y = 8y

-3 x 3y = - 9y

-3 x 7 = - 21

20-21= - 1

8y - 9y = - y

7 0

2 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

so

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

so

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

so

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

so

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago

- <img src="https://tex.z-dn.net/?f=4%20%5Ctimes%205" id="TexFormula1" title="4 \times 5" alt="4 \times 5" align="absmiddle"

Rudik [331]

20 is the answer to the question

4 0

3 years ago

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The correct answer is D but i don’t understand

iren [92.7K]

The answer depends on the way you solved it.

I am assuming you take the base on which you perceived to be: . 5 and height which is 2.

So you must've ended with 1

But in actuality, you need to use the equation above and plug in 1.5 and 1
Subtract them and you should get 1.25

Do the same to the other side, you should get 6.

.125 x 6 = .875

8 0

2 years ago

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