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andre [41]
2 years ago
14

What is an equation of the line that passes through the points (0, -2) and (0,-5)?

Mathematics
1 answer:
choli [55]2 years ago
4 0

Answer:

x = 0

Step-by-step explanation:

We can find slope using this formula:

\frac{y2 - y1}{x2 - x1} = slope

So we plug it in like this:

\frac{-5 - -2}{0-0} = \frac{-3}{0} \\

We see that the slope is undefined so it will be a straight vertical line

So in order to pass through y = -5 and y = -2, x would have to equal 0.

Therefore, the equation is x = 0

<em>Hope this helps!!</em>

<em>- Kay</em>

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What is the sum of the roots of the quadratic equation x²+6x-14=0?​
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Answer:

<h3>Sum of Roots =<u> (-8)</u><u> </u><u> </u></h3><h3>Product of Roots = <u> </u><u> </u><u>(-84)</u><u> </u><u> </u></h3>

Step-by-step explanation:

{x}^{2}  + 6x - 14 = 0

Roots :- 6 and -14

Sum of the roots :

[6 + (-14)]

= (-8)//

Product of the roots :

[(6)(-14)]

= (-84)//

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Evaluate 2.5(8.6/2)-1.8
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Step-by-step explanation:

Given the expression:

2.5( \frac{8.6}{2} ) - 1.8

Follow BODMAS rule.

always evaluate brackets first, followed by multiply or division then addition or subtraction from LEFT to RIGHT.

2.5( \frac{8.6}{2} ) - 1.8 \\  = 2.5(4.3) - 1.8 \\  = 10.75 - 1.8 \\  = 8.95

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Find an equation of a line through √3,1 / 2) parallel to the line:
vagabundo [1.1K]

Answer:

(a) x=\sqrt{3}

(b) y=\frac{1}{2}

(c) Answer of part a is equation of line x=\sqrt{3} which is parallel to y axis and in part by equation of line is y=\frac{1}{2} which is parallel to x axis

Step-by-step explanation:

We have given points are (\sqrt{3},\frac{1}{2})

(a) Equation of line is given x = -9

We have to find the equation of line parallel to x= -9 and passing through (\sqrt{3},\frac{1}{2})

x = -9 line is parallel to y axis and so slope will be infinite

Equation of line is given by y-y_1=m(x-x_1)

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x=\sqrt{3}

(b) Equation of line is given y=-\sqrt{7}

This line is parallel to x axis so slope will be zero

So equation of line will be y-\frac{1}{2}=0(x-\sqrt{3})

y=\frac{1}{2}

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