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oee [108]
3 years ago
12

What equation allows you to calculate the force acting on an object?

Mathematics
2 answers:
Dahasolnce [82]3 years ago
7 0
Force = mass x acceleration 
lys-0071 [83]3 years ago
7 0
Net force= mass times acceleration
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Can u explain to me how to get the answer??
crimeas [40]
Basically all you have to do is to find what the question is telling you and the unit you will get it from the question example: 15 is what percent of 90 so first work out the question then the unit is percent% because they say what percent.
 
hope i helped
7 0
3 years ago
Read 2 more answers
Write 10 places in India and write their population in Indian and international system​
gulaghasi [49]

Answer Expert Verified

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Solution :-

Following are the population of five major cities of India according to the Census of 2011.

1) Mumbai  

a) Indian System :

1,24,42,373 - One Crore Twenty Four Lakh Forty Two Thousand Three Hundred Seventy Three.

b) International system :

12,442,373 - Twelve Million Four Hundred Forty Two Thousand Three Hundred Seventy Three.

2) Delhi  

a) Indian System :  

1,10,34,555 - One Crore Ten Lakh Thirty Four Thousand Five Hundred Fifty Five.

b) International System :

11,034,555 - Eleven Million Thirty Four Thousand Five Hundred Fifty Five.

3) Bangalore  

a) Indian System :

84,43,675 - Eighty Four Lakh Forty Three Thousand Six Hundred Seventy Five.

b) International system :

8,443,675 - Eight Million Four Hundred Forty Three Thousand Six Hundred Seventy Five.

4) Hyderabad  

a) Indian System :

67,31,790 - Sixty Seven Lakh Thirty One Thousand Seven Hundred Ninety.

b) International System :

6,731,790 - Six Million Seven Hundred Thirty One Thousand Seven Hundred Ninety.

5) Ahmedabad  

a) Indian System :  

55,77,940 - Fifty Five Lakh Seventy Seven Thousand Nine Hundred Forty.

b) International System :

5,577,940 - Five Million Five Hundred Seventy Seven Thousand Nine Hundred Forty.

5 0
2 years ago
Read 2 more answers
Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest
NNADVOKAT [17]

Answer:

100%

Step-by-step explanation:

100% of the shelters received 1,000 or fewer cans per month since all the data values in the box and whisker plot are below 1,000 indicating that homeless shelter received more than 1,000 cans.

7 0
3 years ago
How do you do this fraction
JulsSmile [24]
The answer to the question is 11/14
7 0
2 years ago
Read 2 more answers
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 11z on the curve of intersection of the plane x − y + z =
Taya2010 [7]

Answer:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

<em>Maximum value of f=2.41</em>

Step-by-step explanation:

<u>Lagrange Multipliers</u>

It's a method to optimize (maximize or minimize) functions of more than one variable subject to equality restrictions.

Given a function of three variables f(x,y,z) and a restriction in the form of an equality g(x,y,z)=0, then we are interested in finding the values of x,y,z where both gradients are parallel, i.e.

\bigtriangledown  f=\lambda \bigtriangledown  g

for some scalar \lambda called the Lagrange multiplier.

For more than one restriction, say g(x,y,z)=0 and h(x,y,z)=0, the Lagrange condition is

\bigtriangledown  f=\lambda \bigtriangledown  g+\mu \bigtriangledown  h

The gradient of f is

\bigtriangledown  f=

Considering each variable as independent we have three equations right from the Lagrange condition, plus one for each restriction, to form a 5x5 system of equations in x,y,z,\lambda,\mu.

We have

f(x, y, z) = x + 2y + 11z\\g(x, y, z) = x - y + z -1=0\\h(x, y, z) = x^2 + y^2 -1= 0

Let's compute the partial derivatives

f_x=1\ ,f_y=2\ ,f_z=11\ \\g_x=1\ ,g_y=-1\ ,g_z=1\\h_x=2x\ ,h_y=2y\ ,h_z=0

The Lagrange condition leads to

1=\lambda (1)+\mu (2x)\\2=\lambda (-1)+\mu (2y)\\11=\lambda (1)+\mu (0)

Operating and simplifying

1=\lambda+2x\mu\\2=-\lambda +2y\mu \\\lambda=11

Replacing the value of \lambda in the two first equations, we get

1=11+2x\mu\\2=-11 +2y\mu

From the first equation

\displaystyle 2\mu=\frac{-10}{x}

Replacing into the second

\displaystyle 13=y\frac{-10}{x}

Or, equivalently

13x=-10y

Squaring

169x^2=100y^2

To solve, we use the restriction h

x^2 + y^2 = 1

Multiplying by 100

100x^2 + 100y^2 = 100

Replacing the above condition

100x^2 + 169x^2 = 100

Solving for x

\displaystyle x=\pm \frac{10}{\sqrt{269}}

We compute the values of y by solving

13x=-10y

\displaystyle y=-\frac{13x}{10}

For

\displaystyle x= \frac{10}{\sqrt{269}}

\displaystyle y= -\frac{13}{\sqrt{269}}

And for

\displaystyle x= -\frac{10}{\sqrt{269}}

\displaystyle y= \frac{13}{\sqrt{269}}

Finally, we get z using the other restriction

x - y + z = 1

Or:

z = 1-x+y

The first solution yields to

\displaystyle z = 1-\frac{10}{\sqrt{269}}-\frac{13}{\sqrt{269}}

\displaystyle z = \frac{-23\sqrt{269}+269}{269}

And the second solution gives us

\displaystyle z = 1+\frac{10}{\sqrt{269}}+\frac{13}{\sqrt{269}}

\displaystyle z = \frac{23\sqrt{269}+269}{269}

Complete first solution:

\displaystyle x= \frac{10}{\sqrt{269}}\\\\\displaystyle y= -\frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{-23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=-0.4

Complete second solution:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=2.4

The second solution maximizes f to 2.4

5 0
3 years ago
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