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2 years ago

Find the value of Z for the triangles

Mathematics

1 answer:

kolbaska11 [484]2 years ago

4 0

Answer:

z = 17.5

Step-by-step explanation:

segment RX is an angle bisector and divides the opposite side into segments that are proportional to the other 2 sides, that is

$\frac{RS}{RT}$ = $\frac{SX}{TX}$ , substitute values

$\frac{15}{z}$ = $\frac{6}{7}$ ( cross- multiply )

6z = 105 ( divide both sides by 6 )

z = 17.5

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3 years ago

First to answer gets BRAINLEST<br><br> Which graphs show continuous data select all correct answers

solniwko [45]

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Answer:

Graph number 1 and 3

Step-by-step explanation:

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3 years ago

a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no

Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

$\frac{sin A}{a} = \frac{sin B}{b}$

Therefore,

$\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}$

α = Angle between radar and ship α

∴ α = 58.052

Where we put

$\frac{sin 45}{6.25} = \frac{sin \alpha }{x}$ to get

$\frac{x}{6.25} = \frac{sin \alpha }{sin 45}$ and differentiate to get

$\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt} }{sin 45}$

$\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt} }$ = 3.208 degrees/second = 0.05599 rad/sec.

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3 years ago

Help me to solve this one too please?

Flura [38]

Answer:

y = 19.89 ( 19.90 approx. )

Step-by-step explanation:

plz follow me

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2 years ago

What is the solution (x, y) to the system of equations shown?

iren2701 [21]

Answer:

Step-by-step explanation:

Glad to help

If you will have any questions about the way I solved it,

don't hesitate to ask

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3 years ago