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3 years ago

Can someone help me , with math thanks

Mathematics

2 answers:

serious [3.7K]3 years ago

3 0

Answer:

2+w greater than 5

Step-by-step explanation:

w=-3

Ostrovityanka [42]3 years ago

3 0

Answer:

$w = 3$

Step-by-step explanation:

$2 + w > 5 \\ w = 5 - 2 \\ w = 3$

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SOMEONE PLZ HELPPPPP!!!!!

likoan [24]

Answer: Supplementary

7 0

3 years ago

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If X and Y are independent continuous positive random

Leni [432]

a) $Z=\frac XY$ has CDF

$F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy$

where the last equality follows from independence of $X,Y$ . In terms of the distribution and density functions of $X,Y$ , this is

$F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy$

Then the density is obtained by differentiating with respect to $z$ ,

$f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy$

b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Differentiating gives the associated PDF,

$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

and

$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0

3 years ago

Find the value of x?!??????

PilotLPTM [1.2K]

Answer:

x = 31

Step-by-step explanation:

Given:

MN = 20

PQ = x

RS = 42

Required:

Value of x

SOLUTION:

In a trapezoid, the midsegment length equals the sum of both bases divided by 2

This implies that:

PQ = ½(MN + RS)

Plug in the values

x = ½(20 + 42)

x = ½(62)

x = 31

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3 years ago

8/9 in simplest form

tigry1 [53]

Answer:

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2 years ago

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On a test that has a normal distribution, a score of 19 falls one standard deviation below the mean, and a score of 40 falls two

nexus9112 [7]

Hi there!

We can use the following equation:

$\large\boxed{z = \frac{x-\mu}{\sigma}}$

z = amount of standard deviations away a value is from the mean (z-score)

σ = standard deviation

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μ = mean

Plug in the knowns for both and rearrange to solve for the mean:

$-1 = \frac{19-\mu}{\sigma}\\\\-\sigma = 19 - \mu\\\\ \sigma = -19 + \mu$

Other given:

$2 = \frac{40-\mu}{\sigma}\\\\2\sigma = 40- \mu\\\\ \sigma = 20 - \frac{\mu}{2}$

Set both equal to each other and solve:

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5 0

2 years ago