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3 years ago

Can someone solve this real quick and show their work please. don’t answer if you don’t know how to do it:(

Mathematics

1 answer:

kifflom [539]3 years ago

6 0

Answer:

m<b is 62

AB is 14 mi

BC is 7 miles

m<b is 66

AC is 29.3 miles

BC is 7 miles

Step-by-step explanation:

For the measure part triangles have a measure of 180 degrees 90+28 is 118 180- 118 is 62, for the second part you would just add four since its minus four

for the lengths you look at the congruent sides on the opposing triangles

and dont go calling me a nerd, i just like learning, i literally play starting varsity for three sports

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Item 15 Write and solve an equation to find the number n. Eight plus the quotient of a number and 3 is −2. Equation: =−2 The num

BabaBlast [244]

Answer:

n = - 30

Step-by-step explanation:

Eight plus the quotient of a number and 3 is −2

Expressing in mathematical terms, we have;

8 + (n/3) = -2

To solve for n;

Multiply all through by 3.

3*8 + 3(n/3) = 3 * (-2 )

24 + n = - 6

n = -6 - 24

n = - 30

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3 years ago

Someone do this worksheet I’ll give u brainlist and 20 points(SHOW ALL WORK) on a piece of paper!!!

zloy xaker [14]

Answer:

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3 years ago

Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.

We will use half life formula.

$A=a\cdot(\frac{1}{2})^{\frac{t}{h}}$ , where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{1}$

$A=1\text{ kg}\cdot\frac{1}{2}$

$A=0.5\text{ kg}$

Therefore, amount of the material left after 10 days would be 0.5 kg.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{2}$

$A=1\text{ kg}\cdot\frac{1^2}{2^2}$

$A=1\text{ kg}\cdot\frac{1}{4}$

$A=0.25\text{ kg}$

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0

3 years ago

the slide at the playground has a height of 6 feet.The base of the slide measured on the ground is 8 feet.what is the length of

NemiM [27]

The formula for finding the length is
${a}^{2} + {b}^{2} = {c}^{2}$
All we have to do is plug in the numbers.

${6}^{2} + {8}^{2} = {c}^{2}$
36 + 64 = 100

Since 100 =
${c}^{2}$
we have to find the square root.

$\sqrt{100} = 10$

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3 years ago

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wlad13 [49]

Answer: 4

Step-by-step explanation:

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12 = 2*2*3

GCF=2*2

Hope this helps!!

4 0

3 years ago