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dybincka [34]
3 years ago
9

What is: X+2-3= When X=1

Mathematics
2 answers:
VashaNatasha [74]3 years ago
3 0

Answer:

0

Step-by-step explanation:

1+2 =3 3-3=0

Mice21 [21]3 years ago
3 0

Answer:

0

Step-by-step explanation:

If X=1, substitute that value into the equation. x(1) + 2 - 3 = 1 + 2 - 3 = 3 - 3 = 0

Hope this helped! If it did, please mark me as brainliest! :) Thanks!

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Please help me with number 2. I already have number 4. And leave a description on how to do it! Thank you!
Aneli [31]

Since your probably solving for W, isolate W by adding the -3n to both sides and get W=5n now use a calculator and multiply 5 and Pi. To Get 15.7.


I used N for pi since I don’t have that symbol

You need to specify what needs to be solved so I just assumed W

6 0
4 years ago
A triangle has angle measures of 44°,(3x+8), and (4c-12)°. Classify the triangle by its angles
mars1129 [50]

Answer: right

Step-by-step explanation:

5 0
3 years ago
What are two divison ways that can help solve 7divided by 406
Kay [80]
You can round 406to420 then divide by 7 or 406-490 divided by 7
6 0
3 years ago
PLEASE HELP IM ON A TIME LIMIT :(
Mice21 [21]

Answer:

hey hope this helps

<h3 /><h3>Comparing sides AB and DE </h3>

AB =

\sqrt{ {1}^{2} +  {1}^{2}  }

=  \sqrt{2}

DE

= \sqrt{ {(3 - 5)}^{2} +  {(1 + 1}^{2}  }  \\   = \sqrt{ {( - 2)}^{2}  +  {(2)}^{2} }  \\    = \sqrt{4 + 4}  \\  =  \sqrt{8}  \\   = 2 \sqrt{2}

So DE = 2 × AB

and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.

<u>scale factor</u> = AB/DE

= 2

It's been reflected across the Y-axis

<em>moved thru the translation of 3 units towards the right of positive x- axis </em>

for this let's compare the location of points B and D

For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3

so the triangle has been shifted by 3 units across the positive x axis

7 0
3 years ago
Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter tha
raketka [301]

According to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.

We assume the brightness of a dim day to be x.

According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.

Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.

According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.

Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.

Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.

Thus, according to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.

Learn more about the developed scale at

brainly.com/question/4970963

#SPJ1

The question provided is incomplete. The complete question is:

"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?

Dim=2

Illuminated=3

Radiant=4

Dazzling=5"

8 0
1 year ago
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