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AlekseyPX
3 years ago
15

Maura is going on a plane. She can't have a carry-on backpack that weighs more than 10 pounds. She weighed the items she wants t

o pack on a sensitive scale: book: 5.142 pounds, jacket: 3.6 pounds, backpack: 1.28 pounds. What is the total weight of these items? If all of these items are in her backpack, can she take all of these things?
Mathematics
1 answer:
9966 [12]3 years ago
3 0

Answer:

2.098 pounds total these pounds

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Find the missing side length in the image attached.
Aleks [24]

Answer:

? = 56.

Step-by-step explanation:

In the problem, the side 20 corresponds to side 32 and side 20 + 35 corresponds to side 32 + ?.

\frac{20}{32} =\frac{20 + 35}{? + 32}

\frac{5}{8} =\frac{55}{? + 32}

\frac{1}{8}=\frac{11}{? + 32}

? + 32 = 8 * 11

? + 32 = 88

? = 56.

Hope this helps!

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3 years ago
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If Linda wants to know how much time students spend in the library, then she needs to how much people go. That means she needs to ask the first question, "How many hours per week do you read books in the library?".
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3 years ago
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Suppose you need to know an equation of the tangent plane to a surface S at the point P(4, 1, 4). You don't have an equation for
Alex777 [14]

Answer:

15x-8y+9z=88

Step-by-step explanation:

We are given that

Equation of curves

r_1(t)=

r_2(u)=

Both curves lie on S.

We have to find the equation of tangent plane at P(4,1,4).

r'_1(t)=,r'_2(u)=

r_1(0)=, r_2(1)=

Hence, t=0 and u then it satisfied the given point.

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The equation of tangent at point P(4,1,4) is given by

30(x-4)-16(y-1)+18(z-4)=0

30x-120-16y+16+18z-72=0

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4 years ago
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5 0
3 years ago
In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles,
bonufazy [111]

Answer:

Phillipa rode the most in May and rode the least in March.

Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March  

Step-by-step explanation:

Given:

In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles, and in May, she rode 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) miles.

To find: the month when she rode the most and the month when she rode the least

Solution:

Distance travelled by Phillipa on her cycle in April = 13 . 5 + 8 . 7 + 11 . 1 = 65 + 56 + 11 = 132 miles

Distance travelled by Phillipa on her cycle in March = ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 = \frac{132}{2}=66 miles

Distance travelled by Phillipa on her cycle in May = 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) = 4 × 132 = 528 miles

So, she rode the most in May and rode the least in March

Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March  

8 0
3 years ago
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