Answer:
Sabemos que:
L es el largo de la avenida.
En la primer etapa se asfalto la mitad, L/2, entonces lo que queda por asfaltar es:
L - L/2 = L/2.
En la segunda etapa se asfalto la quinta parte, L/5, entonces lo que queda por asfaltar es:
L/2 - L/5 = 5*L/10 - 2*L/10 = (3/10)*L
En la tercer etapa se asfalto la cuarta parte del total, L/4, entonces lo que queda por asfaltar es:
(3/10)*L - L/4 = 12*L/40 - 10L/40 = (2/40)*L
Y sabemos que este ultimo pedazo que queda por asfaltar es de 200m:
(2/40)*L = 200m
L = 200m*(40/2) = 4,000m
Answer: The length is 20.
Step-by-step explanation:
If UW is the line segment, then the length of VW and UV has to equal to the length of UW
VW = 6
UV = 14
6 + 14 = 20
Answer:
yes
Step-by-step explanation:
y=3x + 1
y = -x+5
Check if (1,4) solves the first equation
4 = 3(1)+1
4 = 3+1
4=4
This is true
Check the second equation
4 = -1+5
4=4
This is true
(1,4) is a solution to the system of equations
Width of the reactangle = 38 cm
Minimum perimeter = 692 cm
Let the length of the rectangle be x cm
We know that,
Perimeter of rectangle = 2 * (length + width)
Since the perimeter should be atleast 692 cm. Therefore,
2 * (x + 38) > 692
2x + 76 > 692
2x > 692 - 76
2x > 616
x > 
x > 308
Hence, the length of the rectangle should be more that 308 cms.
The gas exerts a pressure of 218.75 kPa when its volume is reduced to 2.0 L, following the behavior of an ideal gas.
Ideal gas behavior:
Suppose the initial volume of carbon dioxide gas is V = 3.5l
Initial pressure is P = 125 kPa
Since the volume is reduced to 2.0l, the final volume is shown as V'= Will be done. 2L
The final pressure of the gas is P'.
We consider the behavior of gas to be ideal. From the ideal gas equation, it becomes as follows.
PV = P'V'
125 × 3.5 = P'× 2
P'= 218.75 kPa
Therefore, the final pressure is 218.5 kPa.
Learn more about ideal gas, visit brainly.com/question/11676583?referrer=searchResults
#SPJ4
