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Sholpan [36]
2 years ago
7

Solve for x , if x + 47 = -23 . x =

Mathematics
2 answers:
love history [14]2 years ago
6 0

Answer:

-70

Step-by-step explanation:

subtract 47 from both sides to get

x = -23 - 47

cestrela7 [59]2 years ago
4 0

Answer:

Step-by-step explanation:

x + 47=-23

x + 47 - 47=-23 - 47

x=-70

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Un triángulo isósceles ,la altura al lado desigual mide 1 cm mas que longitud de ese lado . Calcula el valor de dicha altura sab
sertanlavr [38]

Answer:

Hence the required dimension is 4cm.

Step-by-step explanation:

Given:

An Isosceles triangle with uneven side=l+1 cm

Area= 6 sq cm

To Find:

Height of Triangle.

Solution:

We know that area of triangle given by,

Area=1/2*base*height.

Here height =1+base

6=1/2((b+1)*b

12=(b+1)*b.

b^2+b-12=0

(b-3)(b+4)=0

b=3 or b=-4

So length never be negative

so b=3 cm

And height=b+1=3+1=4 cm.

4 0
3 years ago
Solve each of the following systems by Gauss-Jordan elimination. (b) X1-2x2+ x3- 4x4=1 X1+3x2 + 7x3 + 2x4=2 -12x2-11x3- 16x4 5 (
Len [333]

Answer:

a) The set of solutions is \{(0,-3x_3,x_3): x_3\; \text{es un real}\} y b) the set of solutions is \{(-6,\frac{-41}{17}-\frac{30}{17}x_4 , \frac{37}{17}+\frac{8}{17} x_4 ,x_4): x_4\;\text{es un real}\}.

Step-by-step explanation:

a) Let's first find the echelon form of the matrix \left[\begin{array}{ccc}5&2&6\\-2&1&3\end{array}\right].

  • We add \frac{2}{5} from row 1 to row 2 and we obtain the matrix \left[\begin{array}{ccc}5&2&6\\0&\frac{9}{5} &\frac{27}{5}\end{array}\right]
  • From the previous matrix, we multiply row 1 by \frac{1}{5} and the row 2 by \frac{5}{9} and we obtain the matrix \left[\begin{array}{ccc}1&\frac{2}{5} &\frac{6}{5} \\0&1&3\end{array}\right]. This matrix is the echelon form of the initial matrix.

The system has a free variable (x3).

  • x2+3x3=0, then x2=-3x3
  • 0=x1+\frac{2}{5}x2+\frac{6}{5}x3=

       x1+\frac{2}{5}(-3x3)+\frac{6}{5}x3=

      x1-\frac{6}{5}x3+\frac{6}{5}x3

     then x1=0.

The system has infinite solutions of the form (x1,x2,x3)=(0,-3x3,x3), where x3 is a real number.

b) Let's first find the echelon form of the aumented matrix \left[\begin{array}{ccccc}1&-2&1&-4&1\\1&3&7&2&2\\0&-12&-11&-16&5\end{array}\right].

  • To row 2 we subtract row 1 and we obtain the matrix \left[\begin{array}{ccccc}1&-2&1&-4&1\\0&5&6&6&1\\0&-12&-11&-16&5\end{array}\right]
  • From the previous matrix, we add to row 3, \frac{12}{5} of row 2 and we obtain the matrix \left[\begin{array}{ccccc}1&-2&1&-4&1\\0&5&6&6&1\\0&0&\frac{17}{5}&\frac{-8}{5}&\frac{37}{5}   \end{array}\right].
  • From the previous matrix, we multiply row 2 by \frac{1}{5} and the row 3 by \frac{5}{17} and we obtain the matrix \left[\begin{array}{ccccc}1&-2&1&-4&1\\0&1&\frac{6}{5} &\frac{6}{5}&\frac{1}{5}\\0&0&1&\frac{-8}{17}&\frac{37}{17} \end{array}\right]. This matrix is the echelon form of the initial matrix.

The system has a free variable (x4).

  • x3-\frac{8}{17}x4=\frac{37}{17}, then x3=\frac{37}{17}+ \frac{8}{17}x4.x2+[tex]\frac{6}{5}x3+\frac{6}{5}x4=\frac{1}{5}, x2+\frac{6}{5}(\frac{37}{17}+\frac{8}{17}x4)+[tex]\frac{6}{5}x4=\frac{1}{5}, then

      x2=\frac{-41}{17}-\frac{30}{17}x4.

  • x1-2x2+x3-4x4=1, x1+\frac{82}{17}+\frac{60}{17}x4+\frac{37}{17}+\frac{8}{17}x4-4x4=1, then x1=1-\frac{119}{17}=-6

The system has infinite solutions of the form (x1,x2,x3,x4)=(-6,\frac{-41}{17}-\frac{30}{17}x4,\frac{37}{17}+ \frac{8}{17}x4,x4), where x4 is a real number.

6 0
3 years ago
1.Explain how to find equivalent fractions for 9/12<br> 2.Explain how to simplify 16/24
krok68 [10]

1.   9/12   divide top and bottom by 3

     3/4

now you can multiply the top and bottom by the same number and get an equivalent fraction

3/4 * 2/2  = 6/8

3/4 * 5/5 = 15/20

these are all equivalent fractions to 9/12 = 3/4 = 6/8 = 15/20


2.  16/24  

divide the top and bottom by 8  

2/3

This is as small as it goes  (keep dividing until there is no number that will go into the top and the bottom evenly).


4 0
3 years ago
Yuki bought a pound of confetti for $ 12 $12dollar sign, 12. What is the price, in dollars, per ounce of confetti? There are 16
Zina [86]

We have been given that bought a pound of confetti for $12. We are asked to find price per ounce of confetti.

We know that 1 pound equals 16 ounces. To find cost of per ounce confetti, we will divide total cost by 16 as:

\text{Cost of per ounce confetti}=\frac{\$12}{16}

\text{Cost of per ounce confetti}=\frac{\$3}{4}

\text{Cost of per ounce confetti}=\$0.75

Therefore, the cost of per ounce confetti is $0.75

7 0
2 years ago
The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i
Anit [1.1K]

Answer:

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The n^{th} term of geometric sequence is given by:

a_n = ar^{n-1}

a_4 = 16 = ar^3\\a_6 = 4 = ar^5

Dividing the two equations, we get,

\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}

the first term can be calculated as:

16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128

Thus, the required geometric sequence is

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

4 0
3 years ago
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