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horsena [70]
3 years ago
12

Select all the points that are on the graph of the equation 4y - 6X equals 12

Mathematics
1 answer:
liraira [26]3 years ago
7 0

Answer:

4ieideerriiiriiieeoeoeoee

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Negitive 8 over 2 divided by 6 over negitive 3 = ??????
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 so -8/2 divided by 6/-3 will become

-8/2 times -3/6

then multiple straight across so -8 x -3 = 24

over 6 time 2 = 12

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Help me please. I don’t understand this math. My math teacher is mean. :(((((
Verdich [7]

Answer:

The height of the given rectangular prism is 5cm.

Step-by-step explanation:

Given that the volume of the rectangular prism is 5cm^3

And length is \frac{3}{4} and width is 1\frac{1}{3}

That is V=5cm^3[/tex] , l=\frac{3}{4}cm and w=1\frac{1}{3}cm

We have the  volume of the rectangular prism V=lwh cubic centimeter

V=lwhcm^3

Substituting the values in above formula

5=\frac{3}{4}\times 1\frac{1}{3}\times h

5=\frac{3}{4}\times \frac{4}{3}\times h

5=1\times h

5=h

Rewritting as below

h=5cm

Therefore the height is 5cm

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Lizzie rolls two dice. What is the probability that the sum of the dice is:
zhenek [66]

Answer:

A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

C. Divisible by 3 and less than 7:

P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

5 0
3 years ago
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