Answer:
![\sin(1395)=-\frac{\sqrt 2}{2}\\\cos(1395)=\frac{\sqrt 2}{2}\\\tan(1395)=-1](https://tex.z-dn.net/?f=%5Csin%281395%29%3D-%5Cfrac%7B%5Csqrt%202%7D%7B2%7D%5C%5C%5Ccos%281395%29%3D%5Cfrac%7B%5Csqrt%202%7D%7B2%7D%5C%5C%5Ctan%281395%29%3D-1)
Step-by-step explanation:
First, instead of doing 1395, let's find its coterminal angles. We can do so by subtracting 360 until we reach a solvable range. So:
![1395-360=1035](https://tex.z-dn.net/?f=1395-360%3D1035)
This is still too high, continue to subtract:
![1035-360=675\\675-360=315\\315-360=-45](https://tex.z-dn.net/?f=1035-360%3D675%5C%5C675-360%3D315%5C%5C315-360%3D-45)
So, instead of 1395, we can use just -45.
So, evaluate each trig function for -45:
1)
![\sin(1395)=\sin(-45)](https://tex.z-dn.net/?f=%5Csin%281395%29%3D%5Csin%28-45%29)
Remember that we can move the negative inside of the sine outside. So:
![=-\sin(45)](https://tex.z-dn.net/?f=%3D-%5Csin%2845%29)
Remember the sine of 45 from the unit circle:
![=-\frac{\sqrt2}{2}](https://tex.z-dn.net/?f=%3D-%5Cfrac%7B%5Csqrt2%7D%7B2%7D)
2)
![\cos(1395)=\cos(-45)](https://tex.z-dn.net/?f=%5Ccos%281395%29%3D%5Ccos%28-45%29)
Remember that we can ignore the negative inside of a cosine function. So:
![=\cos(45)](https://tex.z-dn.net/?f=%3D%5Ccos%2845%29)
Evaluate using the unit circle:
![=\frac{\sqrt 2}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Csqrt%202%7D%7B2%7D)
Now, remember that tangent is sine over cosine. So: "
![\tan(1395)=\tan(-45)=\frac{\sin(-45)}{\cos(-45)}](https://tex.z-dn.net/?f=%5Ctan%281395%29%3D%5Ctan%28-45%29%3D%5Cfrac%7B%5Csin%28-45%29%7D%7B%5Ccos%28-45%29%7D)
We already know them. Substitute:
![=\frac{-\frac{\sqrt 2}{2}}{\frac{\sqrt 2}{2}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B-%5Cfrac%7B%5Csqrt%202%7D%7B2%7D%7D%7B%5Cfrac%7B%5Csqrt%202%7D%7B2%7D%7D)
Simplify:
![=-1](https://tex.z-dn.net/?f=%3D-1)
And we're done!
Answer:
c
Step-by-step explanation:
4*4=16
4*8=32
4*8=32
16+32+32=80
80*2=160
Option c is 160
Answer:
<u><em>Dividing or Subtracting</em></u>
Step-by-step explanation:
You Have 4 tens and you have two ones so 10+10+10+10+2