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GREYUIT [131]
3 years ago
10

A survey of 2380 golfers showed that 366 of them are left-handed. Find a point estimate for p, the population proportion of golf

ers that are left-handed.
Mathematics
1 answer:
cluponka [151]3 years ago
8 0

Answer:

The point estimate is 366/2380

Step-by-step explanation:

Here. we want to find a point estimate for the number of golfers that are left-handed

To get this, we simply divide the number of left-handed golfers by the number of golfers surveyed

Mathematically, this will be 366/2380

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A floor mat for gymnastics is a square with a side length of 14m. What is the area of the floor mat in square metres? Explain?
TEA [102]

Answer:

196 square meters

Step-by-step explanation:

If the floor mat is square and one side is 14m then all sides are 14m. Given this you would find area by multiplying length by width.

L=14 W=14

14x14=196

There are 196 square meters

5 0
3 years ago
What is the equation of a circle with center (-3, -5) and radius 4?
o-na [289]

Answer:

(x+3)^{2} +(y+5)^{2} =16

Step-by-step explanation:

the general equation of a circle is

(x-h)^{2} + (y-k)^{2} =r^{2}

with (h,k) being the centre of the circle and r the radius

8 0
3 years ago
Simplify Help me please with this question!!!!!
Shalnov [3]
F/3= -115 hope this helps bro
3 0
3 years ago
a conical tank with vertex down is 10 feet across the top and 12 feet deep. If water is flowing out of the tank at a rate of 12
TiliK225 [7]

Answer:

The water level is dropping at a rate of 0.24 ft/s

Step-by-step explanation:

Here, we simply want to calculate the change in depth (height of the cone) , given the volume change

Mathematically, we have the volume of a cone as;

V = 1/3 * π * r^2 * h

we are given dv/dt as 12 ft^3/m

dv/dh = 1/3 * π * r^2

Substituting the value for the radius, we have

dv/dh = 1/3 * 22/7 * 4^2 = 50.29

dh/dt = dh/dv * dv/dt

dh/dv = 1/(dv/dh) = 1/50.29

Thus,

dh/dt = 1/50.29 * 12

dh/dt = 0.24 ft/s

3 0
3 years ago
Find the derivative of f(x) = 6x + 2 at x = 1.
earnstyle [38]
f'(x_0)=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=6x+2;\ x_0=1\\\\f'(1)=\lim\limits_{x\to x_0}\dfrac{(6x+2)-(6\cdot1+2)}{x-1}=\lim\limits_{x\to x_0}\dfrac{6x+2-8}{x-1}\\\\=\lim\limits_{x\to x_0}\dfrac{6x-6}{x-1}=\lim\limits_{x\to x_0}\dfrac{6(x-1)}{x-1}=\lim\limits_{x\to x_0}6=6\\\\\\Answer:\boxed{f'(1)=6}
6 0
3 years ago
Read 2 more answers
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