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KatRina [158]
3 years ago
9

Is this a function of not

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0

Answer:

NO!

Step-by-step explanation:

An input can't have more than one output, but output can have multiple inputs.

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1/3x = 5 - 1/3x what is the solution of this equation?
sleet_krkn [62]
<h2>Answer: 15/2 aka 7.5</h2>

2x - 15 = 0    x = 15/2 aka 7.5

Hope this helps!

-zomba

 

                 

6 0
3 years ago
Find the mean, median, mode, and range for the set of numbers.
tatiyna

Answer:

mean: 19

median: 22

mode: 5

range: 30

Step-by-step explanation:

hope this helps :)

8 0
3 years ago
How do you solve for the central area of a polygon?
ycow [4]
Getting the central area of a polygon is not possible. Probably the question refers to the central angle. In a a regular polygon, getting the central angle is that you need to use the formula.

Central Angle of a polygon = 360 degrees / number of sides of a polygon.
Why 360 degrees? Because, a circle has a total of 360 degrees. And a circle is a polygon with no sides.
5 0
3 years ago
Problem 4:
Kipish [7]

Answer:

12cm and 16cm

Step-by-step explanation:

The hypotenuse of the right angle triangle  = 20cm

 let the other two sides be x and y;

 The difference;

                x  = y - 4

Problem:

Find x and y;

Solution:

According to the pythagoras theorem;

    x² + y² = 20²  ------ i

       x² + y² = 400 ----- i

and  x - y = 4 ---- ii

So;   x = 4 + y

Now input the value into equation (i);

  (y + 4)² + y² = 400

   (y+4)(y+4) + y² = 400

    y² + y² + 4y + 4y + 16 = 400

    2y² + 8y + 16 = 400

    2y² + 8y + 16 -400 = 0

   2y² + 8y - 384 = 0;

      y² + 4y - 192 = 0

Factorize the equation;

  y² + 16y - 12y - 192 = 0

  y(y + 16) - 12(y + 16) = 0

  (y-12)(y + 16) = 0

     y -12 = 0 or y+ 16 = 0

     y = 12 or -16

It is not realistic for the length of a body to be a negative value, so y= 12;

   since;

    x - y = 4,

    x = 4 + 12

    x = 16

5 0
4 years ago
A classmate simplified a rational expression below
lara31 [8.8K]
<h2>Part a) </h2><h2>Explain the error in this simplification.</h2>

Given the simplified expression

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)

\:1-2x-4=x^2-x-2

-2x-3=x^2-x-2\:\:

0=x^2-2x-2\:\:

0=\left(x-1\right)\left(x-1\right)

x=1

<u><em>Identifying the Main Error</em></u>

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)   ← ERROR Starts here

<u><em>Here is the Explanation of the Error </em></u>

<u><em /></u>

<u><em /></u>\mathrm{The\:equation\:should\:have\:been\:Multiplied\:by\:LCM=}\left(x-2\right)\left(x+2\right)<em>. </em>In your case you wrongly multiply the equation.

<em><u>CORRECTION</u></em>

<em>HERE IS HOW YOU SHOULD HAVE MULTIPLIED BY </em><em>LCM = (x-2)(x+2):</em>

<em />

1-\frac{2}{x-2}=\frac{x+1}{x+2}

1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)

\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)

<h2>Part b) </h2><h2>Show your work as you correct the error</h2>

Here is the complete correction of the error.

Considering the expression

1-\frac{2}{x-2}=\frac{x+1}{x+2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}x-2,\:x+2:\quad \left(x-2\right)\left(x+2\right)

1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)

\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)

x^2-2x-8=x^2-x-2

x^2-2x-8+8=x^2-x-2+8

x^2-2x=x^2-x+6

-x=6

\frac{-x}{-1}=\frac{6}{-1}

x=-6

3 0
3 years ago
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